 is the diameter of a circle with center P. The coordinates of the endpoints of the diameter are (1, 3) and (6, 6). What are th
e coordinates of point P?
(2, 6)
(2.2, 3)
(2.5, 3.5)
(4.5, 5)
(3.5, 4.5)
(2, 6)
(2.2, 3)
(2.5, 3.5)
(4.5, 5)
(3.5, 4.5)
2 answers:
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Answer:
The vertex of a quadratic equation corresponds to the point where the maximum or minimum value is located.
If the function has a positive leading coefficient, the vertex corresponds to the minimum value.
If it has a negative leading coefficient, the vertex corresponds to the maximum valuevalue
If the vertex is located at
(–2, 0)
The possibilities are
y = (x-2)^2
or,
y = - (x-2)^2
Since the problem tells us the answer, we adopt the positive values
Answer:
y = (x-2)^2
See attached picture
I set this up as an inequality, 
. If you take the cubed root of 800, you get the lower bound of the side length, which is 9.2. Then I just worked my way up until I hit the first number that put me over a volume of 800. That number is 9.29, because 9.28 cubed is 799.1 (not high enough) and 9.29 cubed is 801.8. Therefore, the bounds of the sides exist within a conjunction: 
. That's the best I could come up with to help on that one. Wasn't sure if there was another method you were taught at school. I just used common sense more than any rule.