Simplify both sides of the equation.
<span><span><span>(−7.8)(x)</span>+<span>(−7.8)(6.5)</span></span>=−25.74 </span> <span><span><span>−7.8x+</span>−50.7</span>=−25.74 -> </span>−7.8x−50.7=−25.74
<span>Add 50.7 to both sides.
</span><span><span>−7.8x−50.7</span>+50.7</span>=−25.74+50.7 -> −7.8x = <span>24.96
</span><span>Divide both sides by -7.8.
</span><span>−7.8x /−7.8 </span>= <span>24.96/<span>−<span>7.8
</span></span></span><span>And as a decimal
X= </span><span>−3.2
Hope this helped. (got taken off because I did the steps? oo well)</span>
Answer:
(-3,6)
Step-by-step explanation:
y = 1/3 x +7
y = -2x
The question is asking you to find a value for x that would satisfy both equations.
Since y is equal to y ( y=y) you can set both of these equations equal to each other. You would get:
-2x = 1/3 x +7
now you can do some algebra to isolate the x on one side solving for it, this gives you:
-2x - 1/3 x = 7....... -6/3 x - 1/3 x = 7 ...... -7/3 x = 7 ...... -7x = 21 ..... x = -3
Now you have x = -3, and if you plug this into an equation , lets say the second one since it's easier to solve you get:
y = -2(-3) .... y=6
This means when you graph these two equations they should intersect at the point (-3,6)
the square root of 49 is 7.
7 as in improper fraction is 7over1
<h3>
Answer: QR is 8 units long</h3>
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Explanation:
R is between Q and S and on segment QS, allowing us to say
QR + RS = QS
because of the segment addition postulate.
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Use substitution and solve for QR
QR + RS = QS
QR + 11 = 19
QR = 19 - 11 .... subtracting 11 from both sides
QR = 8
Answer:
d. can be equal to the value of the coefficient of determination (r2).
True on the special case when r =1 we have that 
Step-by-step explanation:
We need to remember that the correlation coefficient is a measure to analyze the goodness of fit for a model and is given by:
![r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7Bn%28%5Csum%20xy%29-%28%5Csum%20x%29%28%5Csum%20y%29%7D%7B%5Csqrt%7B%5Bn%5Csum%20x%5E2%20-%28%5Csum%20x%29%5E2%5D%5Bn%5Csum%20y%5E2%20-%28%5Csum%20y%29%5E2%5D%7D%7D)
The determination coefficient is given by 
Let's analyze one by one the possible options:
a. can never be equal to the value of the coefficient of determination (r2).
False if r = 1 then
b. is always larger than the value of the coefficient of determination (r2).
False not always if r= 1 we have that 
and we don't satisfy the condition
c. is always smaller than the value of the coefficient of determination (r2).
False again if r =1 then we have and we don't satisfy the condition
d. can be equal to the value of the coefficient of determination (r2).
True on the special case when r =1 we have that
