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Sati [7]
3 years ago
11

What is the total number of common tangents that can be drawn to the circles

Mathematics
1 answer:
tester [92]3 years ago
6 0

Answer:

A. 0

Step-by-step explanation:

The circles are concentric. I.e there is no point where the circumferences of both circles ever touch each other. Hence there can be no tangent line possible that can be common to both circles at the same time.

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PLEASE HELP ASAP, FIRST PERSON ANSWERS WILL GIVE BRAINLIST WILL GIVE 20 PTS
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C is the correct answer because in a title, you always want to capitalize the bigger and more describing words. 
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Jessica spent 1/4 of her money on a dress. What percentage of her money did she spent on the dress?
Dmitry_Shevchenko [17]

Answer:

She spent about 25% of the money on a dress.

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3 years ago
Complete the following.(a) Find the greatest common factor (GCF) of 63 and 36.хGCF = 0(b) Use the GCF to factor 63 -36.63 – 36 =
morpeh [17]
Answer:

a) The GCF of 63 and 36 is 9

b)

63-36=9\times(7-4)

Explanation:

a) To find the GCF of 63 and 36, we do the following:

Write 63 and 36 as follows:

\begin{gathered} 63=3\times3\times7 \\ 36=2\times2\times3\times3 \end{gathered}

The common factors are:

3\times3

Therefore, the Greatest Common Factor (GCF) is 9

b) To find the factor 63 - 36

63-36=9\times(7-4)

6 0
11 months ago
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Lerok [7]

Answer do we just answer the question or we also have to do something else?

Step-by-step explanation:

6 0
3 years ago
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When Hiroto is writing, there is 0.920.920, point, 92 probability that there will be no spelling mistakes on a page. One day, Hi
Usimov [2.4K]

Complete question :

When Hiroto is writing, there is 0.92 probability that there will be no spelling mistakes on a page. One day, Hiroto writes an essay that is 11 pages long.

Assuming that Hiroto is equally likely to have a spelling mistake on each of the 11 pages, what is the probability that he will have a spelling mistake on at least one of the pages?

Answer:

0.60

Step-by-step explanation:

The question meets the requirement for a binomial probability distribution :

Recall:

P(x = x) = nCx * p^x * q^(n-x)

Given :

Probability of making a spelling mistake = 1 - p(not making) = 1 - 0.92 = 0.08

Hence,

p = 0.08 ; q = 0.92

n = 11

P(x ≥ 1) = 1 - p(x = 0)

P(x = 0) = 11C0 * 0.08^0 * 0.92^11

P(x = 0) = 1 * 1 * 0.3996373778857415671808

P(x = 0) = 0.399

P(x ≥ 1) = 1 - p(x = 0)

P(x ≥ 1) = 1 - 0.399

P(x ≥ 1) = 0.601

P(x ≥ 1) = 0.60

3 0
2 years ago
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