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Answer:
<em><u>This is called a case 2 image. </u></em><em><u> </u></em>
Explanation:
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<em><u>Mark</u></em><em><u> </u></em><em><u>me as</u></em><em><u> </u></em><em><u>Brainleist</u></em><em><u> </u></em>
<em><u>Pls Follo.w</u></em><em><u> </u></em><em><u>Me</u></em><em><u> </u></em>
<em><u>Drop 3</u></em><em><u> </u></em><em><u>Thx</u></em><em><u> </u></em><em><u>✌️</u></em>
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Based on the calculations, we have the following:
- The area of the sheet of paper is 96 square inches.
- The combined area of the triangle cutouts is equal to 36 square inches.
- The area of the parallelogram is equal to 60 square inches.
- The altitude of the parallelogram is equal to 6.51 square inches.
<u>Given the following data:</u>
- Dimension of paper = 12-inch by 8-inch.
<h3>How to calculate the paper's area.</h3>
Mathematically, the area of the paper is given by this formula:
Area = 96 square inches.
<u>For the four (4) right triangles:</u>
- Dimension 1 = 2 inches by 9 inches.
- Dimension 2 = 3 inches by 6 inches.
Therefore, the combined area of the triangle cutouts is given by:
<h3>The area of the parallelogram.</h3>
This would be determined by subtracting the area of the four (4) right triangles from the areas of the paper as follows:
P = 60 square inches.
<h3>The altitude of the
parallelogram.</h3>
Altitude = 6.51 square inches.
Read more on parallelogram here: brainly.com/question/4459854
<u>Complete Question:</u>
A parallelogram is cut out of a 12-inch by 8-inch sheet of paper. There are four right triangle remnants. Two have the dimensions 2 inches by 9 inches, and the other two have the dimensions 3 inches by 6 inches. The resulting parallelogram has a base of approximately 9.22 inches.