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Ksivusya [100]
4 years ago
13

Are the lines 2y-10x=4 and y-2=5x parallel ??

Mathematics
2 answers:
Kisachek [45]4 years ago
7 0
First line  y=(4+10x)/2=5x+2
Second line : y=5x+2

We see that the two have the same leading coefficient (5) hence they are parallel.<span />
aleksandrvk [35]4 years ago
5 0
Well,

If the slope of the lines are the same, then the lines are parralel.

We need to manipulate 2y - 10x = 4 into y = mx + b form.

Add 10x to both sides
2y = 10x + 4

Divide both sides by 2
y = 5x + 2

Do the same thing with the other equation.

Add 2 to both sides
y = 5x + 2

y = 5x + 2

It appears that, not only are they parallel, but they lie on exactly the same line! If this was a System of Simultaneous Linear Equations, then there would be an infinite number of solutions!<span />
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Answer:

15

Step-by-step explanation:

Set the number of children to n.

The number of adults is, thus, n + 25.

The total price of admission is $720, made up of adult tickets and child tickets.

The children paid $8 per child, or

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The adults paid $15 per adult, or

15 * (n + 25)

These sum of these is equal to the total cost of $720.

8*n + 15*(n + 25) = 720

8n + 15(n + 25) = 720

Multiplying 15 with both n and 25.

8n + 15n + 25*15 = 720

8n + 15n + 375 = 720

Subtracting 375 from both sides.

8n + 15n + 375 - 375 = 720 - 375

8n + 15n = 345

Adding together 8n and 15n.

23n = 345

Dividing both sides by 23.

n = 345/23 = 15

n = 15

As n is the number of children, there are 15 children in the group.

Answer: 15

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