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vovangra [49]
3 years ago
14

There were 500 people at a play. the admission price was $6 for general public and $3 for students. the admission receipts were

$2640. solve a system of equations to find how many students attended.
Mathematics
1 answer:
dem82 [27]3 years ago
5 0
Its 880 i think but hope yhu get it right

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Ms. M wants A LOT of tropical fish, so Mr. M must buy the biggest tank. Which tank should he buy, A or B? How much greater is th
NeX [460]

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tank A is bigger

Step-by-step explanation:

the volume is greater by 3%

8 0
2 years ago
Quickly help me..!!!
NikAS [45]

The answer you have selected is correct. The answer to this question is 90.

5 0
3 years ago
Need help with this math​
Ksenya-84 [330]

Answer:

About 22.7 millions

Step-by-step explanation:

Latin America 58%

App. 39.1 million = 39,100,000

People were born in Latin America:

0.58 x 39100000 = 22,678,000

Round to the nearest tenth million = 22.7 millions

7 0
3 years ago
Simplify <br> 3 2/3 - 2 3/4 =
Rasek [7]

Answer: 11/12

Step-by-step explanation:

1. To solve this problem you can transform the mixed numbers given in the problem to fractions, as you can see below:

3 2/3=(3*3+2)/3=11/3

2 3/4=(4*2+3)/4=11/4

2. Now you must make the substraction of the fraction:

11/3-11/4=11/12

3. Therefore, the answer is 11/12

6 0
3 years ago
⦁ In a simple random sample of 1219 US adults, 354 said that their favorite sport to watch is football. Construct a 95% confiden
fomenos

Answer:

95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is [0.265 , 0.316].

Step-by-step explanation:

We are given that in a simple random sample of 1219 US adults, 354 said that their favorite sport to watch is football.

Firstly, the pivotal quantity for 95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is given by;

        P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } ~ N(0,1)

where, \hat p = proportion of adults in the United States whose favorite sport to watch is football in a sample of 1219 adults = \frac{354}{1219}

           n = sample of US adults  = 1291

           p = population proportion of adults

<em>Here for constructing 95% confidence interval we have used One-sample z proportion statistics.</em>

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5%

                                                    significance level are -1.96 & 1.96}

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } ) = 0.95

<u>95% confidence interval for p</u> = [ \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } , \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } ]

                         = [ \frac{354}{1219}-1.96 \times {\sqrt{\frac{\frac{354}{1219}(1-\frac{354}{1219})}{1219} } , \frac{354}{1219}+1.96 \times {\sqrt{\frac{\frac{354}{1219}(1-\frac{354}{1219})}{1219} } ]

                         = [0.265 , 0.316]

Therefore, 95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is [0.265 , 0.316].

5 0
3 years ago
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