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2 years ago

A recipe calls for 40 oz of meat. How many pounds of meat does the recipe require?

2 answers:

6 0

It would be 2.5 pounds of meat. Since each pound is 16 oz, it would be 2 pounds without going over. 16x2=32. 40-32 is 8, which is half a pound. Do 2.5 pounds.

Scrat [10]2 years ago

3 0

Answer:3

Step-by-step explanation:

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How much money does he have

Andrej [43]

C $1.00

because 1/3 of 15 coins are 5 dimes

15 - 5 = 10 nickels

10 + 5 = 15 coins.

5 dimes= .50 cents

10 nickels= . 50 cents

.50 + .50 = $1.00

$1.00 is C.

*Hope this helped :)

7 0

3 years ago

Read 2 more answers

What 35%as a decimal?<br> Please help!

katrin2010 [14]

The answer is .35 not 3.5

5 0

2 years ago

A bank in the Bay area is considering a training program for its staff. The probability that a new training program will increas

WITCHER [35]

Answer:

$P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68$

See explanation below.

Step-by-step explanation:

For this case we define first some notation:

A= A new training program will increase customer satisfaction ratings

B= The training program can be kept within the original budget allocation

And for these two events we have defined the following probabilities

$P(A) = 0.8, P(B) = 0.2$

We are assuming that the two events are independent so then we have the following propert:

$P(A \cap B ) = P(A) * P(B)$

And we want to find the probability that the cost of the training program is not kept within budget or the training program will not increase the customer ratings so then if we use symbols we want to find:

$P(B' \cup A')$

And using the De Morgan laws we know that:

$(A \cap B)' = A' \cup B'$

So then we can write the probability like this:

$P(B' \cup A') = P((A \cap B)')$

And using the complement rule we can do this:

$P(B' \cup A') = P((A \cap B)')= 1-P(A \cap B)$

Since A and B are independent we have:

$P(A \cap B )=P(A)*P(B) =(0.8*0.4) =0.32$

And then our final answer would be:

$P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68$

5 0

3 years ago

What does 11 meters equal in centimeters

joja [24]

The answer is 1100 centimeters.

4 0

3 years ago

How do you find the sine, cosine, and tangent values on the unit circle not in the first quadrant? Provide an example, and how y

gizmo_the_mogwai [7]

A point (-0.8, 0.6) will be a point on the unit circle in the second quadrant. Since it is a unit circle, its radius is 1, and we have
sin(α) = y = 0.6
cos(α) = x = -0.8
tan(α) = y/x = 0.6/-0.8 = -0.75

The angle is α = arccos(-0.8) ≈ 143.13°

______
For the unit circle, the trig values are always the coordinates or their ratio as shown above, regardless of quadrant.

7 0

2 years ago