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babunello [35]
3 years ago
9

A pomegranate is thrown from ground level straight up into the air at time t=0 with velocity 32 feet per second. Its height at t

ime t seconds is f(t)=−16t2+32t. Find the time tg it hits the ground and the time th it reaches its highest point. What is the maximum height h? Enter the exact answers.
Mathematics
1 answer:
liubo4ka [24]3 years ago
6 0

Answer:

It hit the ground at t=2

It reaches its highest point at t=1

Its maximum height =16

Step-by-step explanation:

The graph of the function of the height will be a parapola opening downward where it's x intercepts = the time where the object hit the ground and its maximum point = the point with the maximum point

The x intercepts are 0 when the object was thrown and 2 when it landed

The x coordinate of the vertex is in the middle of the two x intercepts so it will be 1

Substituting the x coordinate of the vertex gives us the y coordinate of the vertex which is the maximum hight 16

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Based on the graph below, how would you describe the curve?
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The best description of the curve of the given graph is called; A: Many to One Function

<h3>How to interpret function graphs?</h3>

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3 0
2 years ago
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</span><span>
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3 0
3 years ago
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=> 4(7)–2(7+a)=8

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3 0
4 years ago
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