A pomegranate is thrown from ground level straight up into the air at time t=0 with velocity 32 feet per second. Its height at t
ime t seconds is f(t)=−16t2+32t. Find the time tg it hits the ground and the time th it reaches its highest point. What is the maximum height h? Enter the exact answers.
The graph of the function of the height will be a parapola opening downward where it's x intercepts = the time where the object hit the ground and its maximum point = the point with the maximum point
The x intercepts are 0 when the object was thrown and 2 when it landed
The x coordinate of the vertex is in the middle of the two x intercepts so it will be 1
Substituting the x coordinate of the vertex gives us the y coordinate of the vertex which is the maximum hight 16
The angle of elevation is 26.565 (3dp) let h be the end height of the ramp above the ground , l be the length of the ramp and the angle of elevation is (30) i'm not sure, sorry
