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deff fn [24]
3 years ago
7

A teacher promised a movie day to the class that did better, on average, on their test. The box plot shows the results of the te

st:
box plot labeled 2nd period with min at 77, Q1 at 78, median at 89, Q3 at 92, max at 100. Box plot labeled 4th period with min at 72, Q1 at 82.5, median at 89, Q3 at 96, max at 97.5

Which class should get the reward, and why?

a. The 2nd period class should get the reward. They have the highest score, a perfect 100.
b. The 2nd period class should get the reward. They have a higher median.
c. The 4th period class should get the reward. Though the medians are the same, the first and third quartiles are higher, so the students did better on average than in the 2nd period class.
d. The 4th period class should get the reward. Their lowest score is an outlier, and should be thrown out.

Mathematics
1 answer:
ANTONII [103]3 years ago
4 0

Hii!!


I think that the correct answer would be C. I know that it couldn't be A because not everyone in 2nd period got 100% and the average students got below 95%. B no because they do not have the same median. D, I do not think so at all. So I would go with C I think it is relatively the best answer!!


Hope that helps!1

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g(2)=4*4

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f(2)=g(2)

Both is equal to 16

I hope this help you :)

Step-by-step explanation:

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Step-by-step explanation:

................

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Can someone please explain to me how to get this answer?
SIZIF [17.4K]
Answers:
A = 120
b = 45.0
c = 33.2

Side Note: only one triangle is possible
See attached for a visual. I used GeoGebra to draw the triangle.

-------------------------------------------------------------
-------------------------------------------------------------

Explanation:

We are given the following information
B = 35
C = 25
a = 68

We need to find the following
A, b, c

where the lower case letters represent the side lengths; the upper case letters are the angles. The angles are opposite their corresponding sides. For instance, side lowercase b is opposite angle uppercase B. The other letters are positioned the same way.

-----------------------

First use the idea that for any triangle, the three angles (A,B,C) must add to 180 degrees
A+B+C = 180
Replace B and C with 35 and 25. Solve for angle A
A+35+25 = 180
A+60 = 180
A+60-60 = 180-60
A = 120

Now that we know the three angles A = 120, B = 35, C = 25, we can find the missing sides 'b' and 'c'

-----------------------

We will use the law of sines to find side b
sin(A)/a = sin(B)/b
sin(120)/68 = sin(35)/b
b*sin(120) = 68*sin(35) <<--- cross multiply
b = 68*sin(35)/sin(120)
b = 45.037013350222 <<--- use a calculator; this value is approximate
b = 45.0 <<--- round to the nearest tenth

-----------------------

Do the same for side c
sin(A)/a = sin(C)/c
sin(120)/68 = sin(25)/c
c*sin(120) = 68*sin(25) <<--- cross multiply
c = 68*sin(25)/sin(120)
c = 33.1838323365404 <<--- use a calculator; this value is approximate
c = 33.2 <<--- round to the nearest tenth

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3 years ago
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