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liq [111]
4 years ago
12

The application layer in the tcp/ip protocol suite is usually considered to be the combination of ________ layers in the osi mod

el
Computers and Technology
1 answer:
navik [9.2K]4 years ago
8 0
Application Presentation and Session Layers.
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Write the header for a function addOne that accepts a single integer reference parameter and returns nothing. Name the parameter
Butoxors [25]
In C++ it would be: void addOne(int& x);

In C# it would be: void addOne( ref int x)

In JAVA you would have to package the integer inside an object, since it doesn't pass value types by reference.
5 0
4 years ago
What are the tyoe of typical application of mainframe computer<br>​
ioda

Explanation:

  • customer order processing
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  • payroll

hope it is helpful to you

8 0
3 years ago
1) What is y after executing the statements?
balu736 [363]

Answer: d. 12

Explanation: if X = 5, then y = 5 + 1 because in y = x + 1, You are replacing the x with 5.

y is now 6.

Now you are multiplying 6 * 2 because of y * 2. You replace the Y with the 6.

6 * 2 = 12

y = 12 or letter d

6 0
2 years ago
Let’s say you attach four images to accompany an important tweet that you’ve composed in the Hootsuite Compose Box. On Twitter,
Damm [24]
I doub between:

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6 0
4 years ago
C++ Code Outputs.
mojhsa [17]

Answer:

#include

#include

#include

#include

using namespace std;

struct courseInfo{

string name;

int unit;

char grade;

};

struct Student {

string fName;

string lName;

string idNumber;

courseInfo courses[2];

int unitCompleted;

double gpa;

};

Student s;

bool openFile(ifstream &in);

void Print_info_one(Student s);

void Read_info(Student &s);

float Find_points(char c) ;

bool openFile(ifstream &inFile){

string line;

int i=0,k=0;

string fName="", lname="", id="", name1="", name2="";

char grade1, grade2;

int unit1, unit2;

if (inFile.is_open())

{

while (getline(inFile, line))

{

while (line[i] != ',')

{

fName += line[i];

i++;

}

i++;

i++;

while (line[i] != ' ')

{

lname += line[i];

i++;

}

i++;i++;

while (line[i] != ' ')

{

id += line[i];

i++;

}

i++;

int count=0;

while (count <2)

{

name1 += line[i];

i++;

if(line[i] == ' ' ) count++;

}

i++;

grade1 = line[i];

i++;i++;

unit1 = line[i]-'0';

i++;i++;

count=0;

while (count <2)

{

name2 += line[i];

i++;

if(line[i] == ' ' ) count++;

}

i++;

grade2 = line[i];

i++;i++;

unit2 = line[i]-'0';

}

inFile.close();

s.fName = fName;

s.lName = lname;

s.idNumber = id;

s.courses[0].name = name1;

s.courses[0].grade = grade1;

s.courses[0].unit = unit1;

s.courses[1].name = name2;

s.courses[1].grade = grade2;

s.courses[1].unit = unit2;

s.unitCompleted = unit1 + unit2;

s.gpa = (unit1*Find_points(grade1) + unit2*Find_points(grade2))/(unit1+unit2);

}

else

{

cout << "Error reading file\n";

return false;

}

return true;

}

void Print_info_one(Student s){

cout << "Name: " << s.fName << ", " << s.lName << " ID Number: " << s.idNumber << " Course 1 Name: " << s.courses[0].name << " Grade: "

<< s.courses[0].grade << " Units: " << s.courses[0].unit << " Course 2 Name: " << s.courses[1].name << " Grade: "

<< s.courses[1].grade << " Units: " << s.courses[1].unit << " Unit completed: " << s.unitCompleted << " GPA:" << s.gpa << endl;

}

void Read_info(Student &s){

}

float Find_points(char grade){

switch (grade)

{

case 'A':

return 4.0;

break;

case 'B':

return 3.0;

break;

case 'C':

return 2.0;

break;

case 'D':

return 1.0;

break;

case 'F':

return 0;

break;

default:

break;

}

return 0;

}

int main() {

ifstream inFile;

std::fstream fs;

fs.open ("input.txt", std::fstream::in );

Print_info_one(s);

return 0;

Explanation:

5 0
3 years ago
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