We need to compute for the length of each trophy given that one trophy is 5 inches wider than the other.
Let x be the length of the first trophy.
Let x+5 be the length of the second trophy
The solution is shown below:
x + (x + 5) = 17
x + x + 5 =17
2x =17 -5
2x = 12
x = 12/2
x=6 (for the first trophy)
x + 5 = 6+5 = 11 (for the second trophy)
The first trophy is 6 inches wide while the second trophy is 11 inches wide.
Answer:
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Answer:
34
56/19
6
Step-by-step explanation:
∵ z = 8
∴ 4(8) + 8 - 6 =34
∵ x = 3
∴ 7z /(4 + 5x) = 7(8) ÷ (4 + 5 × 3) = 56 ÷ 19 = 56/19
∵ y = 12
∴ y² ÷ 3z = (12)² ÷ 3(8) = 144 ÷ 24 = 6
7x + 5 = -58
+ 5 represents 5 more than
7x represents 7 times a number
First, find the radius of the circle. The radius of a circle is half the diameter. r=13/2=6.5
Second, use the equation A=pi * r^2 to find the area of the circle.
A=(3.14) * (6.5^2) = 132.665m^2
so the answer is 132.7 m^2.