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inysia [295]
3 years ago
13

The price of a stock on February 1 is $84. A trader buys 200 put options on the stock with a strike price of $90 when the option

price is $10. The options are exercised when the stock price is $85. The trader’s net profit or loss is:
A.Loss of $1,000
B.Loss of $2,000
C.Gain of $200
D.Gain of $1000
Business
1 answer:
Andrews [41]3 years ago
7 0

Answer:

The net loss of the trader amounts to $1,000, which means the correct option is A

Explanation:

The payoff is computed as:

Payoff = Strike price - Option's Stock price

where

Strike price is $90

Option's Stock Price is $85

Putting the values above:

Payoff = $90 - $85

= $5 per option

The trader bought 200 options, so the payoff would be:

Payoff = Options × Price per option

= 200 × $5

= $1,000

And the option cost would be:

Option cost = Options × Option Price

= 200 × $10

= $2,000

So, there computing net loss or gain as:

Net loss or gain = Payoff - Option cost

= $1,000 - $2,000

= $1,000 ( net loss)

Therefore, the correct option is A

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7 0
3 years ago
2. You're interested in the proportion of students in your school who favor the elimination of a local curfew on teenagers. Assu
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Answer: The minimum number of students you need if you want the margin of error to be 5% IS 278.

Explanation:

Cochran’s Sample Size Formula gives the minimum number of students as n= \frac{z^{2}pq }{e^{2} }

Where:

   e is the desired level of precision (i.e. the margin of error),

   p is the (estimated) proportion of the population which has the attribute in question and q is 1 – p.

The z-value  for 95% confidence interval is found to be 1.96 in a Z table.

Assuming that half of the teenagers favor the elimination of a curfew: this gives us maximum variability. So p = 0.5 and q=0.5.

Then n= (\frac{1.96^{2}*0.5*0.5 }{0.05^{2} } )

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Rounding up, n= \frac{385 }

But considering that 1000 is a small population,  we can modify the sample size we calculated above formula by using this equation:

s = \frac{n}{1 + \frac{n - 1}{N} }

Where s is the adjusted sample size, n is the original sample size we calculated and N is the population size.

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4 years ago
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