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sleet_krkn [62]
3 years ago
12

BRAINLIEST!!! 2. Determine whether each pair of triangles is similar. Justify your answer.

Mathematics
1 answer:
SIZIF [17.4K]3 years ago
6 0

Answer:

the correct answer is option A.

Step-by-step explanation:

given that JK parallel to MN.

therefore angle JKL = angle LMN

and angle KJL = angle LNM

also angle JLK = angle MLN since vertically opposite angles.

we can say that triangle JLK ~ triangle NML.

as angle K coincides with angle L and angle J coincides with angle N

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Right triangle FGH has midsegments of 15,36, and 39 centimeters given that area of a triangle is represented by the formula A=1/
Schach [20]

Answer:

Step-by-step explanation:

according to the midsegment theorem, a midsegment of a triangle is parallel to a side of a triangle and its length is 1/2 length of the side.

1/2FG= 15, SO FG=30,

1/2 GH=36 SO GH=72

AREA = 1/2(72*30)=1080 CM^2

3 0
3 years ago
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List the ages of your family and find the average age<br> 55,34,26,24,19,17
Dmitriy789 [7]

Answer:

<em><u>Soln</u></em><em><u>:</u></em><em><u> </u></em><em><u> </u></em>

<em> </em><em> </em><em> </em><em> </em>

<em> </em><em>Total</em><em> </em><em>ages</em><em> </em><em>=</em><em> </em><em>1</em><em>7</em><em>5</em>

<em> </em><em> </em><em>No</em><em>.</em><em> </em><em>of</em><em> </em><em>ages</em><em>=</em><em> </em><em>6</em><em> </em>

<em> </em><em>Now</em><em>,</em>

<em>A</em><em>verage </em><em>age</em><em>=</em><em> </em><em><u>T</u></em><em><u>otal</u></em><em><u> </u></em><em>ages</em><em>/</em><em>no</em><em>.</em><em> </em><em>of</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>ages</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>1</em><em>7</em><em>5</em><em>/</em><em>6</em><em> </em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>2</em><em>9</em><em>.</em><em>1</em><em>6</em><em>7</em><em> </em><em>ans</em><em>.</em>

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Mamont248 [21]

Answer:

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i am not sure tho

5 0
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2. Two angles have a common vertex but no common side. How can you tell whether the angles are vertical angles?
Maksim231197 [3]

Explanation:

The angles are <em>vertical angles</em> if the opposites of the rays forming one of the angles are the rays forming the other angle.

More formally, if V is the common vertex, and ...

  • R is a point on one of the rays forming Angle 1
  • S is a point on the ray that is the opposite of ray VR
  • T is a point on the other ray forming Angle 1
  • U is a point on the ray that is the opposite of ray VT

Then angle RVT and angle SVU are vertical angles.

___

Another way to say this is that points R, V, S are collinear, as are points T, V, U, and the two angles of interest are RVT and SVU.

If the above conditions cannot be met, then the angles are not vertical angles.

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Hi I Think The Answer is:

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