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Schach [20]
3 years ago
15

David is standing on the deck of his treehouse which is 60 feet high in the tree and looking down at a 59degree angle. In the di

stance, he sees a deer.
How far is the deer from the tree in the nearest tenths of afoot?
Mathematics
1 answer:
lidiya [134]3 years ago
5 0

Answer:

22 degrees.

Step-by-step explanation:

Please find the attachment.

We have been given that a man is in a tree-house 10 feet above the ground. He is looking at the top of another tree that is 22 feet tall.The bases of the trees are 30 feet apart.

To find the angle of elevation from the man's feet to the top of the tree, we will use tangent because we know adjacent side and opposite side to angle x.

Now, we will use arctan or inverse tan to solve for x as:

Upon rounding to nearest degree, we will get:

Therefore, the angle of elevation from the man's feet to the top of the tree is approximately 22 degrees.

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3 years ago
Fourteen less than eight times a number is three more than four times the number. What is the number?
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Answer:

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and

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Step-by-step explanation:

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7 0
3 years ago
(3.6x10^-5)÷(1.8x10^2) in standard form
Lerok [7]

<u>Answer: </u>

The standard form of \left(3.6 \times 10^{-5}\right) \div\left(1.8 \times 10^{2}\right) is 0.0000002

<u>Solution: </u>

We have to write \left(3.6 \times 10^{-5}\right) \div\left(1.8 \times 10^{2}\right) in standard form.

=\frac{3.6 \times 10^{-5}}{1.8 \times 10^{2}}

By dividing 3.6 by 1.8 we get “2”, hence the above equation becomes,

=\frac{2 \times 10^{-5}}{10^{2}}

We know that \frac{x^{a}}{x^{b}}=x^{a-b}

Therefore the above equation becomes,

=2 \times 10^{-5-2}

=2 \times 10^{-7}

since the exponent of 10 is negative , therefore 7 zeros are written on the left hand side of the number.

= 0.0000002

Hence the standard form of \left(3.6 \times 10^{-5}\right) \div\left(1.8 \times 10^{2}\right) is 0.0000002

7 0
4 years ago
Read 2 more answers
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