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Pavel [41]
3 years ago
11

Find the number in the form x3579x that is divisible by 42.

Mathematics
1 answer:
sveticcg [70]3 years ago
7 0

Answer:

335790

Step-by-step explanation:

42=2×3×7

unit digit should be even.

sum of digits should be divisible by 3

3+5+7+9=24÷3=8

sum of other two digits should be multiple of 3

let us consider 335790

3+0=3=3×1

also 0 is even.

335790÷42=7995

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Find the difference between the result of one sixth of product of 10 and 3 multiplied by 4 and 30
kherson [118]

Answer:

10 or -10,

Read the explanation

Step-by-step explanation:

Rewrite this problem as a numerical expression. As per the wording of this problem, there can be two expressions derived.

1.     ((\frac{1}{6}(10*3)*4)-30

2.     30-((\frac{1}{6}(10*3)*4)

Simplify, remember the order of operations. The order of operations is the sequence by which one is supposed to perform operations in a numerical expression. This order is the following:

1. Parenthesis

2. Exponents

3. Multiplication or division

4. Addition or Subtraction

Use this sequence when simplifying and solving the expression:

Expression 1

((\frac{1}{6}(10*3)*4)-30\\\\=((\frac{1}{6}(30)*4)-30\\\\=(5*4)-30\\\\=20 - 30\\\\= -10

Expression 2

30-((\frac{1}{6}(10*3)*4)\\\\=30-((\frac{1}{6}(30)*4)\\\\=30-(5*4)\\\\= 30-20\\\\= 10

6 0
3 years ago
X(x) + 12x + 21 = 0 factor
Yakvenalex [24]
It is not factorable. Factors of 21 are. 21 and 1
7 and 3. None of those add up to 12
3 0
3 years ago
Help please with these questions
Sonja [21]
6.) triangles; 6 units
7.) 5 x 6; 30 units
8.) 72 units
9.) 84 units

Hope this helps!
7 0
3 years ago
High School Pre Cal
krok68 [10]
We know that
1) Sandra can run a mile in 6 minutes-------> 6*60-----> 360 sec
2) 4 laps around the track equals 1 mile
so
4 laps around the track in 360 sec
1 lap in 360/4--------> 90 sec
3) the position of Sandra for t=90 sec must be equal to the point S (0,56)
I proceed to analyze each case for t=90 sec

case a) x(t)=-140 cos(pi*t/45)    y(t)=112 sin(pi*t/45)
x(t)=-140 cos(pi*90/45)------> -140
y(t)=112 sin(pi*90/45)-------> 0
the position is the point (-140,0)------> is not the point S

case b) x(t)=140 sin(pi*t/90)  y(t)=-112 cos(pi*t/90)

x(t)=140 sin(pi*90/90)------> 0
y(t)=-112 cos(pi*90/90)-------> 112
the position is the point (0,112)------> is not the point S
<span>
case c) x(t)=-70 sin(pi*t/45)  y(t)=56 cos(pi*t/45)
</span>x(t)=-70 sin(pi*90/45)------> 0
y(t)=56 cos(pi*90/45) -------> 56
the position is the point (0,56)------> is equal to the point S----> is the solution

case d) x(t)=70 cos(pi*t/90)  y(t)=-56 sin(pi*t/90)

x(t)=70 cos(pi*90/90)------> -70
y(t)=-56 sin(pi*90/90)-------> 0
the position is the point (-70,0)------> is not the point S

 therefore

the answer is the option C

x(t)=-70 sin(pi*t/45)  y(t)=56 cos(pi*t/45)


7 0
3 years ago
Addison studies a tarantula that is 30 mm long suppose she uses a microscope to magnify the spider by 4×10 to the second power h
Debora [2.8K]
The magnification factor is given as 4(10)^2=400. Therefore multiplying this by the spider's actual length will give its apparent length.(400)(30 mm) = 12,000This gives an apparent length of 12,000 mm.
Since 1,000 mm = 1 m, this apparent length is also equivalent to 12 m.

3 0
4 years ago
Read 2 more answers
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