Answer: Our required probability would be 0.70.
Step-by-step explanation:
Since we have given that
Number of players = 14
Number of players have recently taken a performance enhancing drug = 3
Number of players have not recently taken a performance enhancing drug = 14-3=11
Number of members chosen randomly = 5
We need to find the probability that at least one of the tested players is found to have taken a performance enhancing drug.
P(Atleast 1) = 1 - P(none is found to have taken a performance enhancing drug)
So, P(X≥1)=1-P(X=0)

Hence, our required probability would be 0.70.
Answer:
7777
Step-by-step explanation:
You have to do 2 5/8 4 times but in a picture or scrap
It’s the 9 because it’s 3 times 3
Answer:
LN=10
Step-by-step explanation:
if LM = 5 and MN = 5 then LN=10