Answer:
The final ballance will be $1300.37.
Step-by-step explanation:
In this case we have a compounded interest, in order to calculate the final balance we need to use the following formula:
S = P(1 + r/n)^(n*t)
Where S is the final balance, P is the initial investment, r is the rate of interest, t is the time and n is the rate at which it is compounded. Since we have all the values we can directly apply to the formula as follows:
S = 975.52*(1 + 0.0725/4)^(4*4)
S = 975.52*(1.018125)^(16)
S = 975.52*1.333
S = 1300.37
The final ballance will be $1300.37.
55% of 1800 = 0.55(1800) = 990...so there are 990 girls in the school
30% of 990 = 0.30(990) = 297...so there are 297 girls who take the bus
The measure of angle (m ∠A) is 136°
<h3>Vertical angles theorem</h3>
From the question, we are to find the measure of angle A
From the given information, we have that
∠A and ∠B are vertical angles
Thus
∠A = ∠B
and
Also, from the given information,
m ∠A=(2x+26)°
and
m ∠B= (3x−29)°
∴ (2x+26)° = (3x−29)°
Now, solve for x
2x + 26 = 3x - 29
26 + 29 = 3x - 2x
55 = x
∴ x = 55
But measure of angle A is given by
m ∠A=(2x+26)°
Put the value of x into the equation,
m ∠A=(2(55)+26)°
m ∠A=(110+26)°
m ∠A = 136°
Hence, the measure of angle (m ∠A) is 136°
Learn more on Vertical angle theorem here: brainly.com/question/24839702
#SPJ1
Answer:
V = (About) 22.2, Graph = First graph/Graph in the attachment
Step-by-step explanation:
Remember that in all these cases, we have a specified method to use, the washer method, disk method, and the cylindrical shell method. Keep in mind that the washer and disk method are one in the same, but I feel that the disk method is better as it avoids splitting the integral into two, and rewriting the curves. Here we will go with the disk method.
![\mathrm{V\:=\:\pi \int _a^b\left(r\right)^2dy\:},\\\mathrm{V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy}](https://tex.z-dn.net/?f=%5Cmathrm%7BV%5C%3A%3D%5C%3A%5Cpi%20%5Cint%20_a%5Eb%5Cleft%28r%5Cright%29%5E2dy%5C%3A%7D%2C%5C%5C%5Cmathrm%7BV%5C%3A%3D%5C%3A%5Cint%20_1%5E3%5C%3A%5Cpi%20%5Cleft%5B%5Cleft%281%2B%5Cfrac%7B2%7D%7By%7D%5Cright%29%5E2-1%5Cright%5Ddy%7D)
The plus 1 in '1 + 2/x' is shifting this graph up from where it is rotating, but the negative 1 is subtracting the area between the y-axis and the shaded region, so that when it's flipped around, it becomes a washer.
![V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy,\\\\\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx\\=\pi \cdot \int _1^3\left(1+\frac{2}{y}\right)^2-1dy\\\\\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\= \pi \left(\int _1^3\left(1+\frac{2}{y}\right)^2dy-\int _1^31dy\right)\\\\](https://tex.z-dn.net/?f=V%5C%3A%3D%5C%3A%5Cint%20_1%5E3%5C%3A%5Cpi%20%5Cleft%5B%5Cleft%281%2B%5Cfrac%7B2%7D%7By%7D%5Cright%29%5E2-1%5Cright%5Ddy%2C%5C%5C%5C%5C%5Cmathrm%7BTake%5C%3Athe%5C%3Aconstant%5C%3Aout%7D%3A%5Cquad%20%5Cint%20a%5Ccdot%20f%5Cleft%28x%5Cright%29dx%3Da%5Ccdot%20%5Cint%20f%5Cleft%28x%5Cright%29dx%5C%5C%3D%5Cpi%20%5Ccdot%20%5Cint%20_1%5E3%5Cleft%281%2B%5Cfrac%7B2%7D%7By%7D%5Cright%29%5E2-1dy%5C%5C%5C%5C%5Cmathrm%7BApply%5C%3Athe%5C%3ASum%5C%3ARule%7D%3A%5Cquad%20%5Cint%20f%5Cleft%28x%5Cright%29%5Cpm%20g%5Cleft%28x%5Cright%29dx%3D%5Cint%20f%5Cleft%28x%5Cright%29dx%5Cpm%20%5Cint%20g%5Cleft%28x%5Cright%29dx%5C%5C%3D%20%5Cpi%20%5Cleft%28%5Cint%20_1%5E3%5Cleft%281%2B%5Cfrac%7B2%7D%7By%7D%5Cright%29%5E2dy-%5Cint%20_1%5E31dy%5Cright%29%5C%5C%5C%5C)
Our exact solution will be V = π(4In(3) + 8/3). In decimal form it will be about 22.2 however. Try both solution if you like, but it would be better to use 22.2. Your graph will just be a plot under the curve y = 2/x, the first graph.
Answer:
1) x = 14°, y = 5°
2) x = 18.5°, y = 37°
Step-by-step explanation:
1) ∠AOC and ∠BOD are vertical angles, then ∠BOD = 25°
∠MOD = ∠MOB + ∠BOD = 90°
3x + 23° + 25° = 90°
3x = 90° - 23° - 25°
x = 42°/3
x = 14°
∠LOB = ∠LOM + ∠MOB = 90°
5y + 3x + 23° = 90°
5y = 90° - 23° - 3(14°)
y = 25°/5
y = 5°
2) ∠AOC and ∠BOD are vertical angles, then ∠BOD = 16°
∠EOB = ∠EOD + ∠DOB = 90°
2y + 16° = 90°
y = (90° - 16°)/2
y = 37°
∠DOF = ∠BOF + ∠DOB = 90°
4x + 16° = 90°
x = (90° - 16°)/4
x = 18.5°
