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leva [86]
3 years ago
12

Help plz thanks question 1

Mathematics
2 answers:
Varvara68 [4.7K]3 years ago
6 0
-2x^2 + 500x - 350

You need to plug in the equations for C(x) and R(x) into the equation P(x)= R(x) - C(x) and solve.
anzhelika [568]3 years ago
5 0
We will do exactly what the question asks and we will Subtract C(x) from R(x) to discover P(x):

P(x) = R(x) - C(x)
P(x) = (-2x^{2} + 900x - 200) - (400x + 150)
P(x) = -2x^{2} + 900x - 400x + 150  - 200
<span>P(x) = </span>-2x^{2} + 500x - 50

Hope this helps! 
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4) Solve ∆ABC, a = 2.5 cm, c = 3.6 cm, and ∠A = 43°. Begin by sketching and labelling
mezya [45]

The length of b and angle B and C are 3cm, 45  degrees and 79 degrees respectively.

<h3>How to determine the parameters</h3>

To determine the angles and length of sides, we use the sine rule

The sine rule is thus:

\frac{sin A}{a} = \frac{sin B}{b} = \frac{sin C}{c}

Given;

  • a = 2. 5cm
  • c = 3. 6cm
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Let's find angle C

\frac{sin 43}{2. 5} = \frac{sin C}{3. 6}

cross multiply

0. 682 × 3. 6 = sin C × 2. 5

sin C = 2. 4552/ 2. 5

C = sin^-^1(0. 982)

C = 79°

To find length of b

b= \sqrt{c^2 - a^2}

substitute the values

b = \sqrt{3.6^2 - 2. 5^2}

b = \sqrt{6. 71}

b = 2. 59 cm

b = 3cm

To find angle B, we have

\frac{sin 43}{2. 5} = \frac{sin B}{2. 59}

cross multiply

0. 682 × 2. 59= sin B × 2. 5

sin B = 0. 7065

B = sin^-^1(0. 7065)

B = 45°

Hence, the length of b and angle B and C are 3cm, 45  degrees and 79 degrees respectively.

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Can you guys please help me? Thanks!
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