Answer:
so can't see the graph
Step-by-step explanation:
but if you can give a picture of the graph i could help out.
2t^2+1
Subtract t^2 from 3t^2 you get 2t^2
which is 2t^2+1 answer
Class A: 6v + 8b = 202
Class B: 12v + 16b = 284
Solve using the elimination method:
since 6v and 12v are perfect for elimination, multiply the class A equation by 2 so that the van variable cancels out:
12v + 16b = 404
12v + 10b = 284
Then subtract the bottom equation from the top:
6b = 120
b = 20
Now you know that each bus can hold 20 students.
Just plug this into one of the original equations to solve for vans:
6v + 8(20) = 202
6v + 160 = 202
6v = 42
v=7
So then you know that each van can hold 7 students.
Check:
12 (7) + 10 (20) = 284
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Answer:
YZX, YXZ, ZXY, XZY
Step-by-step explanation:
