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zysi [14]
2 years ago
9

Eliminate the parameter,t, in the parametric equation, x=6cos t, and y =3 sin t

Mathematics
1 answer:
german2 years ago
6 0
X = 6 cos(t) 
y = 3 sin(t)

we can rewrite these equations as:

\frac{x}{6}=cost(t) \\ \\ \frac{y}{3} =sin(t)

Taking squares of both equations we get:

( \frac{x}{6})^{2}=sin^{2} (t) \\  \\ 
( \frac{y}{3})^{2}=cos^{2}(t)

Adding both the equations, we get:

\frac{ x^{2} }{36}+ \frac{ x^{2} }{9}=sin^{2}(t)+cos^{2}(t)   \\  \\ 
 \frac{ x^{2} }{36}+ \frac{ x^{2} }{9}=1
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I need help in this please! thank you so much!
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Answer:

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Therefore p(2)=1, p(4)=-1 means that when p(x) is divided x-2 and x-4 is 1 and -1 respectively.

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