All categories

3 years ago

I need help in this asap

Mathematics

2 answers:

RoseWind [281]3 years ago

7 0

The volume of a cylinder is V=pi(R^2)h, so in this case, you would plug in V=(3.14)(4^2)(11) = (3.14)(16)(11) = 552.64 cm^3 because volume is expressed in units cubed

Lemur [1.5K]3 years ago

3 0

The volume of the cylinder is <span>552.92</span>

You might be interested in

annie adds 2 spoonfuls of sugar to her tea and sophie adds 3 spoonfuls to her tea. If one spoonful is 4 grams of sugar and a a c

Tresset [83]

240%

Step-by-step explanation:

if there is 240 grams then you just put a percent sing but are you asking What is the percentage of sugar in each cup? by spoons?

3 0

3 years ago

I spent $10 dollars out $25 what is percent I spent

Lina20 [59]

$\text {Percentage spent = } \dfrac{10}{25} \times 100$

$\text {Percentage spent = } \dfrac{2}{5} \times 100$

$\text {Percentage spent = } 40 \%$

3 0

3 years ago

Read 2 more answers

Please help me with these 4 question i will mark brainliest to correct answer please dont play around

crimeas [40]

Answer:

6, the property of addition.

Step-by-step explanation:

If you add 6 to both sides you used addition lol. Hope I helped, I'm not too good at explaining math sorry

8 0

3 years ago

Solve y'' + 10y' + 25y = 0, y(0) = -2, y'(0) = 11 y(t) = Preview

svetlana [45]

Answer: The required solution is

$y=(-2+t)e^{-5t}.$

Step-by-step explanation: We are given to solve the following differential equation :

$y^{\prime\prime}+10y^\prime+25y=0,~~~~~~~y(0)=-2,~~y^\prime(0)=11~~~~~~~~~~~~~~~~~~~~~~~~(i)$

Let us consider that

$y=e^{mt}$ be an auxiliary solution of equation (i).

Then, we have

$y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.$

Substituting these values in equation (i), we get

$m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.$

So, the general solution of the given equation is

$y(t)=(A+Bt)e^{-5t}.$

Differentiating with respect to t, we get

$y^\prime(t)=-5e^{-5t}(A+Bt)+Be^{-5t}.$

According to the given conditions, we have

$y(0)=-2\\\\\Rightarrow A=-2$

and

$y^\prime(0)=11\\\\\Rightarrow -5(A+B\times0)+B=11\\\\\Rightarrow -5A+B=11\\\\\Rightarrow (-5)\times(-2)+B=11\\\\\Rightarrow 10+B=11\\\\\Rightarrow B=11-10\\\\\Rightarrow B=1.$

Thus, the required solution is

$y(t)=(-2+1\times t)e^{-5t}\\\\\Rightarrow y(t)=(-2+t)e^{-5t}.$

6 0

3 years ago

Find the sum of the interior angles of a convex hexagon?

Dovator [93]

Answer:

720

Step-by-step explanation:

5 0

3 years ago