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Lol, I couldn't figure out how to write it out, but I do think that it's right. But if not I'm sorry!
Just divide them 12 divided by 2 is..... and from there on u go
Answer:
10
Step-by-step explanation:
Let a be the amount needed of 70% pure antifreeze, and let b be the amount needed of 95% pure antifreeze.
0.7a + 0.95b = 180 * 0.9 .........(1)
a + b = 180 .............................(2)
b = 180 - a ..............................(3)
Plugging the expression for b in equation (3) into equation (1), we get:
0.7a + 0.95(180 - a) = 162 ......(4)
Solving equation (4) gives the value a = 36, and plugging this value for a into equation (2) we get b = 144.
Amounts needed are therefore 36 gallons of 70% pure antifreeze and 144 gallons of 95% pure antifreeze.