What is the answer of f(x)=5 exponent x

Find the value of x to the nearest tenth. tan 34° = 20

Likurg_2 [28]

Answer:

The value of x = 13.5.

Step-by-step explanation:

In this question x is missing.

So, the question would be:

tan 34° = x/20.

Now, to find the value of $x$ :

$tan 34 = \frac{x}{20}$

$\frac{x}{20} = tan 34$

Multiplying both sides by 20 we get:

$x=tan 34\times 20$

On simplifying both sides we get:

$x=13.49$

So, to get the value of $x=13.49$ to nearest tenth is 13.5. As we see in hundredth place it is 9 and 4 in tenth place, so after rounding to tenth place 4 will change to 5 so the value is 13.5.

Therefore, the value of x = 13.5.

7 0

2 years ago

What’s equivalent to 1/3 with the denominator of 6

podryga [215]

Answer:

2/6

Step-by-step explanation:

Ok, so if the fraction is 1/3 and the denominator needs to be 6, then what you do is figure out what would turn 3 into 6. So, 3 x 2 would equal 6 and then you would have to also keep that two and multiply that 2 with the 1 and you would get 2. That would lead to the numerator being 2 and the denominator being 6, or 2/6.

8 0

3 years ago

Read 2 more answers

Prove that H c G is a normal subgroup if and only if every left coset is a right coset, i.e., aH = Ha for all a e G

Kaylis [27]

$\Rightarrow$

Suppose first that $H\subset G$ is a normal subgroup. Then by definition we must have for all $a\in H$ , $xax^{-1} \in H$ for every $x\in G$ . Let $a\in G$ and choose $(ab)\in aH$ ( $b\in H$ ). By hypothesis we have $aba^{-1} =abbb^{-1}a^{-1}=(ab)b(ab)^{-1} \in H$ , i.e. $aba^{-1}=c$ for some $c\in H$ , thus $ab=ca \in Ha$ . So we have $aH\subset Ha$ . You can prove $Ha\subset aH$ in the same way.

$\Leftarrow$

Suppose $aH=Ha$ for all $a\in G$ . Let $h\in H$ , we have to prove $aha^{-1} \in H$ for every $a\in G$ . So, let $a\in G$ . We have that $ha^{-1} =a^{-1}h'$ for some $h'\in H$ (by the hypothesis). hence we have $aha^{-1}=h' \in H$ . Because $a$ was chosen arbitrarily we have the desired .