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myrzilka [38]
4 years ago
11

Find the surface area of the figure below.

Mathematics
2 answers:
wel4 years ago
7 0

Answer:

108 inch.

Step-by-step explanation:

To make it a bit easier, I calculated the area of each side of the prism that was shown.

1. Start with the triangular sides: 3 × 4/2 = 6. Since there are two triangular surfaces, you add them together. In the end, you have 12 inch.

2. Calculate the surface with the dimensions 8 in. with 5 in.: 8 × 5 = 40 inch.

3. Calculate the surface with the dimensions 4 in. with 8 in.: 4 × 8 = 32 inch.

4. Calculate the surface with the dimensions 3 in. with 8 in.: 3 × 8 = 24 inch.

5. Last step - add all the results together: 12 + 40 + 32 + 24 = 108 inch.

Hope it helped!!

kicyunya [14]4 years ago
4 0

Answer:

108 i think

Step-by-step explanation:

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Q.6. The equation of the ellipse whose centre is at the origin and the x-axis, the major axis, which passes
azamat

<h3>Answer:</h3>

Equation of the ellipse = 3x² + 5y² = 32

<h3>Step-by-step explanation:</h3>

<h2>Given:</h2>

  • The centre of the ellipse is at the origin and the X axis is the major axis

  • It passes through the points (-3, 1) and (2, -2)

<h2>To Find:</h2>

  • The equation of the ellipse

<h2>Solution:</h2>

The equation of an ellipse is given by,

\sf \dfrac{x^2}{a^2} +\dfrac{y^2}{b^2} =1

Given that the ellipse passes through the point (-3, 1)

Hence,

\sf \dfrac{(-3)^2}{a^2} +\dfrac{1^2}{b^2} =1

Cross multiplying we get,

  • 9b² + a² = 1 ²× a²b²
  • a²b² = 9b² + a²

Multiply by 4 on both sides,

  • 4a²b² = 36b² + 4a²------(1)

Also by given the ellipse passes through the point (2, -2)

Substituting this,

\sf \dfrac{2^2}{a^2} +\dfrac{(-2)^2}{b^2} =1

Cross multiply,

  • 4b² + 4a² = 1 × a²b²
  • a²b² = 4b² + 4a²-------(2)

Subtracting equations 2 and 1,

  • 3a²b² = 32b²
  • 3a² = 32
  • a² = 32/3----(3)

Substituting in 2,

  • 32/3 × b² = 4b² + 4 × 32/3
  • 32/3 b² = 4b² + 128/3
  • 32/3 b² = (12b² + 128)/3
  • 32b² = 12b² + 128
  • 20b² = 128
  • b² = 128/20 = 32/5

Substituting the values in the equation for ellipse,

\sf \dfrac{x^2}{32/3} +\dfrac{y^2}{32/5} =1

\sf \dfrac{3x^2}{32} +\dfrac{5y^2}{32} =1

Multiplying whole equation by 32 we get,

3x² + 5y² = 32

<h3>Hence equation of the ellipse is 3x² + 5y² = 32</h3>
8 0
3 years ago
Solve for the variable in the following equation: 1 / 6c + 1 / 3 = - 2
tankabanditka [31]

Answer: C. C=-14

Step-by-step explanation:

Given

(1/6)c+1/3=-2

Multiply both sides by the LCM of 1/6 and 1/3(Least Common Multiple)

6[(1/6)c+1/3]=(-2)(6)

c+2=-12

Subtract 2 on both sides

c+2-2=-12-2

c=-14

Hope this helps!! :)

Please let me know if you have any questions

4 0
3 years ago
Read 2 more answers
Please help me please!
Mumz [18]

Step-by-step explanation:

a,b) you can place all 17 in the middle and both circle will have 17 each. then remove 2 and place one each on separate sides. you can do this 8 times so that at the you'll end up with 1 in the middle and 8 each on separate sides.

the ways to do is then 9.

7 0
3 years ago
Please help me on this
Stolb23 [73]

Answer:

AX = 14

Step-by-step explanation:

The medians of a triangle intersect at its centroid.

The position of the centroid X from the vertex A is

AX = \frac{2}{3} AL = \frac{2}{3} × 21 = 14

5 0
3 years ago
The diagram below shows two
LiRa [457]

Answer:

4 cm

Step-by-step explanation:

\frac{8}{ST}  = \frac{4}{2} \\\\ST = 8*2 / 4\\ST = 4

6 0
3 years ago
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