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Dahasolnce [82]
2 years ago
15

Jonah is going to the store to buy candles. Small candles cost $2.50 and large candles cost $7.00. He needs to buy at least 20 c

andles, and he can spend no more than 80 dollars. Make this into a system of linear inequalities to model each situation. DEFINE YOUR VARIABLES! (No Solving is required, just equation.)
Mathematics
1 answer:
artcher [175]2 years ago
3 0

<em><u>The system of linear inequalities are:</u></em>

a + b \geq 20\\\\2.50a + 7b\leq 80

<em><u>Solution:</u></em>

Let "a" be the number of small candles bought

Let "b" be the number of large candles bought

<em><u>He needs to buy at least 20 candles</u></em>

Therefore, number of small candles and number of large candles bought must be at least 20

Thus, we frame a inequality as:

a + b \geq 20

"at least" means greater than or equal to

Here, we used "greater or equal to" symbol because, he can buy 20 candles or more than 20 candles also

From given,

Cost of 1 small candle = $ 2.50

Cost of 1 large candle = $ 7

<em><u>He can spend no more than 80 dollars</u></em>

Which means, he spend maximum 80 dollars or less than 80 dollars also

So we have to use "less than or equal to" symbol

<em><u>Thus, we frame a inequality as:</u></em>

Number of small candles bought x Cost of 1 small candle + number of large candles bought x Cost of 1 large candle \leq 80

a \times 2.50 + b \times 7 \leq 80\\\\2.50a + 7b\leq 80

<em><u>Thus the system of linear inequalities are:</u></em>

a + b \geq 20\\\\2.50a + 7b\leq 80

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Which of the following is the solution to 6/(x+2) = 5/4x?
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Answer:

i can help with a littel bit of it

Step-by-step explanation:

1. answer

29±95‾‾‾√9

x

=

−

2

9

±

95

i

9

=−0.222222+1.08298

x

=

−

0.222222

+

1.08298

i

=−0.222222−1.08298

x

=

−

0.222222

−

1.08298

i

Find the Solution for:

92+4+11=0

9

x

2

+

4

x

+

11

=

0

using the Quadratic Formula where

a = 9, b = 4, and c = 11

=−±2−4‾‾‾‾‾‾‾‾√2

x

=

−

b

±

b

2

−

4

a

c

2

a

=−4±42−4(9)(11)‾‾‾‾‾‾‾‾‾‾‾‾√2(9)

x

=

−

4

±

4

2

−

4

(

9

)

(

11

)

2

(

9

)

=−4±16−396‾‾‾‾‾‾‾‾‾√18

x

=

−

4

±

16

−

396

18

=−4±−380‾‾‾‾‾√18

x

=

−

4

±

−

380

18

The discriminant 2−4<0

b

2

−

4

a

c

<

0

so, there are two complex roots.

Simplify the Radical:

=−4±295‾‾‾√18

x

=

−

4

±

2

95

i

18

=−418±295‾‾‾√18

x

=

−

4

18

±

2

95

i

18

Simplify fractions and/or signs:

=−29±95‾‾‾√9

x

=

−

2

9

±

95

i

9

which becomes

=−0.222222+1.08298

x

=

−

0.222222

+

1.08298

i

=−0.222222−1.08298

2. Answer:

=−38±895‾‾‾‾√40

x

=

−

3

8

±

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i

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x

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−

0.375

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0.747914

i

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0.375

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i

3. Answer:

=0=−74

x

=

0

x

=

−

7

4

=0

x

=

0

=−1.75

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8

x

2

+

14

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+

0

=

0

using the Quadratic Formula where

a = 8, b = 14, and c = 0

=−±2−4‾‾‾‾‾‾‾‾√2

x

=

−

b

±

b

2

−

4

a

c

2

a

=−14±142−4(8)(0)‾‾‾‾‾‾‾‾‾‾‾‾√2(8)

x

=

−

14

±

14

2

−

4

(

8

)

(

0

)

2

(

8

)

=−14±196−0‾‾‾‾‾‾‾√16

x

=

−

14

±

196

−

0

16

=−14±196‾‾‾‾√16

x

=

−

14

±

196

16

The discriminant 2−4>0

b

2

−

4

a

c

>

0

so, there are two real roots.

Simplify the Radical:

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x

=

−

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±

14

16

=016=−2816

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=

0

16

x

=

−

28

16

=0=−74

x

=

0

x

=

−

7

4

which becomes

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x

=

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=−1.75

i hope this helps

8 0
2 years ago
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