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Dahasolnce [82]
3 years ago
15

Jonah is going to the store to buy candles. Small candles cost $2.50 and large candles cost $7.00. He needs to buy at least 20 c

andles, and he can spend no more than 80 dollars. Make this into a system of linear inequalities to model each situation. DEFINE YOUR VARIABLES! (No Solving is required, just equation.)
Mathematics
1 answer:
artcher [175]3 years ago
3 0

<em><u>The system of linear inequalities are:</u></em>

a + b \geq 20\\\\2.50a + 7b\leq 80

<em><u>Solution:</u></em>

Let "a" be the number of small candles bought

Let "b" be the number of large candles bought

<em><u>He needs to buy at least 20 candles</u></em>

Therefore, number of small candles and number of large candles bought must be at least 20

Thus, we frame a inequality as:

a + b \geq 20

"at least" means greater than or equal to

Here, we used "greater or equal to" symbol because, he can buy 20 candles or more than 20 candles also

From given,

Cost of 1 small candle = $ 2.50

Cost of 1 large candle = $ 7

<em><u>He can spend no more than 80 dollars</u></em>

Which means, he spend maximum 80 dollars or less than 80 dollars also

So we have to use "less than or equal to" symbol

<em><u>Thus, we frame a inequality as:</u></em>

Number of small candles bought x Cost of 1 small candle + number of large candles bought x Cost of 1 large candle \leq 80

a \times 2.50 + b \times 7 \leq 80\\\\2.50a + 7b\leq 80

<em><u>Thus the system of linear inequalities are:</u></em>

a + b \geq 20\\\\2.50a + 7b\leq 80

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STALIN [3.7K]

Answer:

9.6558916e+17

Scientific Notation: 3.45 x 10^5

E Notation: 3.45e5

= 9.26 × 1010

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(scientific e notation)

= 92.6 × 109

(engineering notation)

(billion; prefix giga- (G))

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Step-by-step explanation:

somewhere between those lines, good luck!

5 0
2 years ago
Can someone please help me.
Katena32 [7]
Given 
- f(n) values for n=1,2,3,4
- possible candidates for the function

Solution:
Method: Evaluate some of the values, for each function.  A function with ANY value not matching the given f(n) values will be rejected.

N=1, f(n)=4
f(1)=4-3(1-1)=4
f(1)=4+3^(1+1)=4+3^2=4+9=13 &ne; 4   [rejected]
f(1)=4(3^(n-1))=4(3^0)=4
f(1)=3(4^(n-1))=3(4^0)=3*1=3  [rejected]

N=2, f(n)=12
f(1)=4-3(2-1)=4-3(1)=1 &ne; 12   [rejected]
[rejected]
f(1)=4(3^(2-1)=4*3^1=4*3=12
[rejected]

Will need to check one more to be sure
N=3, f(n)=3
[rejected]
[rejected]
f(3)=4(3^(n-1))=4(3^(3-1))=4(3^2)=4*9=36   [Good]
[rejected]

Solution: f(n)=4(3^(n-1))










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Step-by-step explanation:

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