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3 years ago

How do you solve this system , y=1/2x-4 and y=-2x+1 by graphing

Mathematics

1 answer:

mart [117]3 years ago

7 0

Answer:

x=2

y=-3

Step-by-step explanation:

we have

$y=\frac{1}{2}x-4$ ----> equation A

$y=-2x+1$ ----> equation B

Solve the system by graphing

Remember that the solution of the system of equations by graphing is the intersection point both lines.

using a graphing tool

The intersection point is (2,-3)

therefore

The solution is

x=2

y=-3

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Which explicit formula describes the sequence -9,-3,3,9,15...?

dalvyx [7]

Answer:

the answer for your question is b

7 0

3 years ago

How to solve this I don’t get this material

Nata [24]

6^2+(24/6+3^2)
First, solve the powers.
6^2=6*6=36
3^2=3*3=9
Now substitute.
36+(24/6+9)
Solve the parentheses.
36+(4+9)
Then, solve.
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3 years ago

Solve for x.<br> z=(x-7)k

aliya0001 [1]

Answer:

$x=\frac{z}{k}+7$

Step-by-step explanation:

we have

$z=(x-7)k$

solve for x

That means ----> isolate the variable x

Divide by k both sides

$\frac{z}{k}=x-7$

Adds 7 both sides

$\frac{z}{k}+7=x$

Rewrite

$x=\frac{z}{k}+7$

5 0

3 years ago

A three-bend saddle will only fit tight if the radius of the obstruction is equal to or less than the radius of the bend.

Dima020 [189]

Answer:

True

Step-by-step explanation:

A three-bend saddle consists of a center bend and 2 side bends with the center bend having twice the angle of the side bends. Therefore, the radius of the obstruction has to be equal or less than the radius of the bend in order to fit tightly

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3 years ago

evaluate the fermi function for an energy KT above the fermi energy. find the temperature at which there is a 1% probability tha

dybincka [34]

Complete Question

Evaluate the Fermi function for an energy kT above the Fermi energy. Find the temperature at which there is a 1% probability that a state, with an energy 0.5 eV above the Fermi energy, will be occupied by an electron.

Answer:

The Fermi function for the energy KT is $F(E_o) = 0.2689$

The temperature is $T_k = 1261 \ K$

Step-by-step explanation:

From the question we are told that

The energy considered is $E = 0.5 eV$

Generally the Fermi function is mathematically represented as

$F(E_o) = \frac{1}{e^{\frac{[E_o - E_F]}{KT} } + 1 }$

Here K is the Boltzmann constant with value $k = 1.380649 *10^{-23} J/K$

$E_F$ is the Fermi energy

$E_o$ is the initial energy level which is mathematically represented as

$E_o = E_F + KT$

$F(E_o) = \frac{1}{e^{\frac{[[E_F + KT] - E_F]}{KT} } + 1}$

=> $F(E_o) = \frac{1}{e^{\frac{KT}{KT} } + 1}$

=> $F(E_o) = \frac{1}{e^{ 1 } + 1}$

=> $F(E_o) = 0.2689$

Generally the probability that a state, with an energy 0.5 eV above the Fermi energy, will be occupied by an electron is mathematically represented by the Fermi function as

$F(E_k) = \frac{1}{e^{\frac{[E_k - E_F]}{KT_k} } + 1 } = 0.01$