Answer: it depends on how big each bowl could be. depending on how big the diameter of the bowl is, we can figure out what the radius is, and then we could multiply that by pi squared, which gets you the area of the circle. Then we could figure out how much larger the large bowl is than the smaller bowl with the diameter knowledge that we gained.
So, for example, there was a bowl like this: (|||) (imagine that is a full circle) and that would be... about 9 in. across. imagine the smaller bowl is about 3in. across. then, we could figure out the radius by finding the middle, and expand the middle to the edge of the bowl. then, whatever the radius is, we could multiply that by 8, and get the total diameter of the bowl in inches. with that knowledge, we should be able to know the area of the bowl, by getting the diameter, and multiplying it by pi squared which equals 9.42, and then you multiply that by the radius and the diameter to get the area of the bowl.
that is how you could figure out how much bigger the large bowl is than the smaller bowl.
Hello There!
The "Inter-Quartile Range" is 9
Answer:
C
Step-by-step explanation:
The costs of each game was A. $3.50
$21 - $7\4 = $3.50
The answer is 8x^2 - 4x. you find it using the distributive property
