Answer: 0.8202
Step-by-step explanation:
Probability an adult was never in a museum = probability of success = p = 15% = 0.15
To find probability that 2 or fewer of the 10 samples selected were never in a museum is given by:
P(X=2) or P(X=1) or P(X=0).
Where
P(X=r) = nCr * p^r * q^n-r
and n=10, p =0.15, q=0.85
When r = 2
P(X=2) = 10C2 * 0.15² * 0.85^8 = 0.2759
When r = 1
P(X=1) = 10C1 * 0.15 * 0.85^9 = 0.3474
When r = 0
P(X=0)= 10C0 * 0.15^0 * 0.85^10 = 0.1969
Hence probability of having 2 or fewer adults who never visited the museum = 0.1969 + 0.3474+ 0.2759 = 0.8202
4 kings total out of 52 cards
1 king was picked so 3 are left, 52 -1 = 51 cards left
so you have a 3/51 reduced to a 1/17 probability of picking another king
We can split this up into 3 rectangles. 2 vertical ones (8 x 3) and one horizontal one in the middle (5 x (8 - 5)
8 x 3 = 24
24 x 2 = 48
5 x (8-5) = 5 x 3 = 15
now add 48 + 15 = 63 cm^2
Treat the ottoman as a cylinder.
area of the top surface is πr²=π*16²
The total lateral area (the side) is: π*d*h=2*16*π*(6+8)=28*16π (diameter is twice the radius, so d=2*16)
the area of the green part is: π*d*8=2*16**8π=16*16π
not including the bottom, the total area is the top plus the total side:16²π+16*28π=(16+28)*16π=44*16π
the percent of the green part is: 16²π/44*16π=16/44≈36%
Is 36% a choice?
Answer:
the answer would be 33.....
