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3 years ago

Simplify. 9 – (–6) – 12 27 –15 –9 3

Mathematics

1 answer:

Ipatiy [6.2K]3 years ago

8 0

-1320 is the answer if the 12 27 is supose to be written as 1227

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49767269 x 327686000 - 1029 + 1101 / 32

mars1129 [50]

Answer:

$16308037309533006\frac{13}{32}$

Step-by-step explanation:

49767269 × 327686000 - 1029 + $\frac{1101}{32}$

= 16308037309534000 - 1029 + $\frac{1101}{32}$

= 16308037309532972 + $34\frac{13}{32}$

= $16308037309533006\frac{13}{32}$

8 0

3 years ago

Marisol sells wedding cakes. She charges a flat fee of $245 to make the wedding cake, plus an additional $120 per tier of cake.

leva [86]

Answer:

120x + 245 = y

x = number of additional tiers

(edited to be in the proper order)

8 0

3 years ago

What is the value of this expression when a = 3 and b = -2?

weqwewe [10]

The first step: Simplify the expression with:

$\dfrac{x^n}{x^m}=x^{n-m}\\\\(xy)^n=x^ny^n\\\\(x^n)^m=x^{nm}\\\\x^{-n}=\dfrac{1}{x^n}$

$\left(\dfrac{3a^{-2}b^6}{2a^{-1}b^5}\right)^2=\left(\dfrac{3}{2}a^{-2-(-1)}b^{6-5}\right)^2=\left(\dfrac{3}{2}a^{-1}b^1\right)^2\\\\=\left(\dfrac{3}{2}\right)^2(a^{-1})^2b^2=\dfrac{9}{4}a^{-2}b^2=\dfrac{9b^2}{4a^2}$

The second step: Put the values of a = 3 and b = -2 to the expression:

$\dfrac{9(-2)^2}{4(3)^2}=\dfrac{(9)(4)}{(4)(9)}=1$

<h2>Answer: 1</h2>

4 0

4 years ago

Read 2 more answers

The figure below is a diagram of a trapezoidal table that needs to be stained. Each can of stain will cover 50 square inches.

alekssr [168]

The perimeter is the sum of the outside dimensions.

b1 = 87 - 32 - 14 - 13 = 28 in.

Area = (32 + 28) /2 x 12 = 60/2 x 12 = 30 x 12 = 360 square inches.

Divide area by the amount 1 can covers:

360 / 50 = 7.2 cans, round up to 8 cans are needed.

7 0

3 years ago

Which equations are true for x = –2 and x = 2? Select two options

Rudik [331]

The equations that are true for x = -2 and x = 2 are (a) x^2 - 4 = 0 and (d) 4x^2 = 16

<h3>How to determine the true equations?</h3>

We have:

x = -2 and x = 2

Rewrite as:

x + 2 = 0 and x - 2 = 0

Multiply both equations

(x + 2)(x - 2) = 0

This gives

x^2 - 4 = 0 --- option (a)

Add 4 to both sides

x^2 = 4

Multiply by 4

4x^2 = 16 --- option (d)

Hence, the equations that are true for x = -2 and x = 2 are (a) x^2 - 4 = 0 and (d) 4x^2 = 16