Question

Frank is making a pennant in the shape of a triangle for his senior class photo. He wants the base length of this triangle to be 6 inches. The area of the pennant must be at most 27 square inches. (Frank doesn't want to buy more materials.) Write an inequality that describes the possible heights (in inches) of the triangle.
Use h for the height of the triangular pennant.

Answer 1

Answer:

Height should be ≤ 9 inches.

Step-by-step explanation:

Given:

Frank is making a pennant in the shape of a triangle for his senior class photo.

Base of triangle = 6 in

Area of triangle ≤ 27 $in^2$

Let height of the triangle be h

Now we now that,

Area of triangle = $\frac{1}{2}\times base \times height$

$\frac{1}{2}\times 6 \times h \leq 27\\\\3h\leq 27\\\\h\leq \frac{27}{3}\\\\h\leq 9 \ in.$

Hence the height of the triangle must be at most or ≤ 9 inches.