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I am Lyosha [343]
3 years ago
15

An online store lets customers have their name printed on any item they buy. the total cost c in dollars is the price of the ite

m p in dollars plus $3.99 for the name.

Mathematics
1 answer:
Vsevolod [243]3 years ago
4 0
So the total cost depends on the price of the item(s) (c depends on p)
The independent variable is p, the price of the item, because it is not going to depend on anything else.
The dependent variable is c, because the total cost depends on how many items there are, whether your name is marked on it, etc.
The equation would be :
c = p + $3.99

I hope this was helpful!
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A square window has an area of 196
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Answer:

14 feet

Step-by-step explanation:

s2 = 196

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Triangle KNM is shown. Triangle K N M is shown. Angle M K N is 25 degrees. Angle K N M is 130 degrees. Angle N M K is 25 degrees
mars1129 [50]

Answer:

<h3>Two of the sides of triangle KNM are the equal</h3>

Step-by-step explanation:

From the triangle KNM, we can see that two of the angles M K N and Angle N M K are the same. If two of the angles are equal this means that two of the sides of the triangles are also equal. This type of triangle is known as an ISOSCELES TRIANGLE.

An isosceles triangle is a triangle that has two of its angles and sides to be equal.

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3 years ago
What is the measure of ∠D?
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63

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3 0
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A point is chosen randomly on AD. What is the probability that the point is on BC?
Nadusha1986 [10]
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How to know if a function is periodic without graphing it ?
zhenek [66]
A function f(t) is periodic if there is some constant k such that f(t+k)=f(k) for all t in the domain of f(t). Then k is the "period" of f(t).

Example:

If f(x)=\sin x, then we have \sin(x+2\pi)=\sin x\cos2\pi+\cos x\sin2\pi=\sin x, and so \sin x is periodic with period 2\pi.

It gets a bit more complicated for a function like yours. We're looking for k such that

\pi\sin\left(\dfrac\pi2(t+k)\right)+1.8\cos\left(\dfrac{7\pi}5(t+k)\right)=\pi\sin\dfrac{\pi t}2+1.8\cos\dfrac{7\pi t}5

Expanding on the left, you have

\pi\sin\dfrac{\pi t}2\cos\dfrac{k\pi}2+\pi\cos\dfrac{\pi t}2\sin\dfrac{k\pi}2

and

1.8\cos\dfrac{7\pi t}5\cos\dfrac{7k\pi}5-1.8\sin\dfrac{7\pi t}5\sin\dfrac{7k\pi}5

It follows that the following must be satisfied:

\begin{cases}\cos\dfrac{k\pi}2=1\\\\\sin\dfrac{k\pi}2=0\\\\\cos\dfrac{7k\pi}5=1\\\\\sin\dfrac{7k\pi}5=0\end{cases}

The first two equations are satisfied whenever k\in\{0,\pm4,\pm8,\ldots\}, or more generally, when k=4n and n\in\mathbb Z (i.e. any multiple of 4).

The second two are satisfied whenever k\in\left\{0,\pm\dfrac{10}7,\pm\dfrac{20}7,\ldots\right\}, and more generally when k=\dfrac{10n}7 with n\in\mathbb Z (any multiple of 10/7).

It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when k is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.

Let's verify:

\sin\left(\dfrac\pi2(t+20)\right)=\sin\dfrac{\pi t}2\underbrace{\cos10\pi}_1+\cos\dfrac{\pi t}2\underbrace{\sin10\pi}_0=\sin\dfrac{\pi t}2

\cos\left(\dfrac{7\pi}5(t+20)\right)=\cos\dfrac{7\pi t}5\underbrace{\cos28\pi}_1-\sin\dfrac{7\pi t}5\underbrace{\sin28\pi}_0=\cos\dfrac{7\pi t}5

More generally, it can be shown that

f(t)=\displaystyle\sum_{i=1}^n(a_i\sin(b_it)+c_i\cos(d_it))

is periodic with period \mbox{lcm}(b_1,\ldots,b_n,d_1,\ldots,d_n).
4 0
3 years ago
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