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oksian1 [2.3K]
3 years ago
5

What does this number represent ​

Mathematics
1 answer:
nekit [7.7K]3 years ago
3 0

answer is: a number to the third power divided by ten. pls mark brainliest!!

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Is 3⁵ the same as 3 • 5? Please Explain ​
Katena32 [7]

Answer:

No. 3^5 = 3 * 3 * 3 * 3 * 3, which does not equal 3 * 5.

5 0
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$4000 at 3% for 4 years
tankabanditka [31]

Answer:$4,502.04

Step-by-step explanation:

This is assuming your interest is compounded annually.

can be easily calculated by providing inputs on below link.

https://www.investor.gov/additional-resources/free-financial-planning-tools/compound-interest-calculator

4 0
4 years ago
Solve each equation for y. Then find the value of y for each value of x. y+3x=8;x=-2,0,2
damaskus [11]
Y=-3x+8
when x=-2:
y=-3(-2)+8
y=6+8
y=14
when x=0
y=-3(0)+8
y=0+8
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when x=2
y=-3(2)+8
y=-6+8
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6 0
3 years ago
More free points cause I’m the goat ya dig
denis23 [38]

Answer:

YO! THANKS!

Step-by-step explanation:

3 0
4 years ago
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Claim amounts for wind damage to insured homes are independent random variables with common density f(x) = ( 3 x4 , x > 1 0 ,
Irina-Kira [14]

f_X(x)=\begin{cases}\dfrac3{x^4}&\text{for }x>1\\\\0&\text{otherwise}\end{cases}

This distribution has expectation

E[X]=\displaystyle\int_{-\infty}^\infty xf_X(x)\,\mathrm dx=\int_1^\infty\frac3{x^3}\,\mathrm dx=\frac32

a. The probability that X falls below the average/expectation is

P\left(X

b. Denote by X_{(3)} the largest of the three claims X_1,X_2,X_3. Then the density of this maximum order statistic is

f_{X_{(3)}}(x)=3f_X(x)F_X(x)^2

where F_X(x)=P(X\le x) is the distribution function for X. This is given by

F_X(x)=\displaystyle\int_{-\infty}^xf_X(t)\,\mathrm dt=\begin{cases}0&\text{for }x

So we have

f_{X_{(3)}}(x)=\begin{cases}0&\text{for }x1\end{cases}

and the expectation is

E[X_{(3)}]=\displaystyle\int_{-\infty}^\infty xf_{X_{(3)}}(x)\,\mathrm dx=\int_1^\infty\frac9{x^3}\left(1-\frac1{x^3}\right)^2\,\mathrm dx=\frac{81}{40}=\boxed{2.025}

c. Denote by X_{(1)} the smallest of the three claims. X_{(1)} has density

f_{X_{(1)}}(x)=3f_X(x)(1-F_X(x))^2=\begin{cases}0&\text{for }x1\end{cases}

so the expectation is

E[X_{(1)}]=\displaystyle\int_{-\infty}^\infty xf_{X_{(1)}}(x)\,\mathrm dx=\int_1^\infty\frac9{x^9}\,\mathrm dx=\frac98=\boxed{1.125}

3 0
4 years ago
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