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JulijaS [17]
4 years ago
7

One reason for _____ is efficiency. People can perform more efficiently if they master just one distinct task rather than all ta

sks. a. job rotation b. job sharing c. job enrichment d. flextime e. job specialization
Business
2 answers:
quester [9]4 years ago
7 0

Answer: Job Specialization

Explanation:

Job specialization involves allocating  people  to different tasks of the process. people must focus solely on the task or job allocated to him or her. People may be allocated according to their education or training   relevant to that task or they may be allocated according to what each person is good at. Performing one job every day you become an expert in doing that particular job or task and that will improve efficiency.

Job Specialization is most suitable for A production process that involves different phases where a unit goes through different phases of production before it is presented as a finished product, Allocating people for each phase and solely focus on the work performed on that phase will increase efficiency rather than having every one performing all stages of production.

Job specialization makes it easy even for the firm to provide specialized training for employees and measure their progress and efficiency in performing that job. When every phase of the  production process is performed efficiently there will efficiency in the overall production process

drek231 [11]4 years ago
4 0

Answer:

e. job specialization

Explanation:

Job specialization is the process of adequately training a specific set of people and equipping them with specific skills to perform and concentrate on a specific job for which they are trained for mainly. It involves placing individuals in specific job areas that match their area of expertise mainly. Such individuals concentrate mainly on their area of expertise with little or no chance of working in other areas out of their area of expertise.

One major advantage of job specialization is that, efficiency is increased as individuals concentrate on their specific area of expertise to get tasks effectively completed with minimal supervision.

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Handy Home sells windows and doors in the ratio of 7:3 (windows:doors). The selling price of each window is $111 and of each doo
Setler [38]

Answer:

1.

Selling Price $156

2.

Variable cost $101.25

Break-even 9,500 units and $1,482,000

Explanation:

Compposit unit unit is a unit made according to the propostion to sale. Different products are combined to make a sales mix for composit unit.

1.

Selling price per composit unit = [ ( 7 x 111 ) + ( 3 x 261 ) ] / 10 = 1560 / 10 = $156

2.

Variable cost per composit unit = [ ( 7 x 68 ) + ( 3 x 180.5 ) ] / 10 = 1,017.5 / 10 = $101.75

Contribution per composit unit = Selling Price - variable cost = $156 - 101.75 = $54.25

Break-even Point = Total Fixed cost / Contribution per unit = $515,375 / 54.25 = 9,500 units

Break-even Point ($ value )= 9,500 x 156 = $1,482,000

8 0
3 years ago
Mister Jones was selling his house. The asking price was $220,000, and Jones decided he would take no less than $200,000. After
user100 [1]

Answer:

D) not able to be calculated from the information given.

Explanation:

Consumer surplus is the difference between willingness to pay of a consumer and the price actually paid for a good or service.

The price paid by Smith is $205,000 but there's no information on the willingness to pay of Smith. Therefore, the consumer surplus can't be calculated.

I hope my answer helps you.

5 0
3 years ago
Salaries for professions (such as architect or medical doctor) that require a long period of study are typically higher than tho
andrew-mc [135]

Answer:

d. future income is worth less than present income

Explanation:

Remember, since we want an exception to all the possible reasons for higher salaries of those in medical and architectural profession, we carefully examine the reasons given.

However, in no way is it because those of this profession (architect, medical doctors) would earn future income worth less than their present income a basis for their higher salaries than other jobs, since most often they earn more as they the years goes by in their profession.

8 0
3 years ago
Larry Bar opened a frame shop and completed these transactions: 1. Larry started the shop by investing $41,500 cash and equipmen
Anit [1.1K]

Answer: $44,800

Explanation:

Given that,

Investment = $41,500

cash and equipment = $19,500

Office supplies purchases on credit = $220

Paid cash for the receptionist's salary = $2700

Cash received from selling custom frame service = $6000

Framing services =  $350

Ending cash flow = Capital brought in by Larry Bar - Paid cash for the receptionist's salary + Cash received from selling custom frame service

                            = $41,500 - $2700 + $6000

                            = $44,800

7 0
3 years ago
Suppose that output (Y ) in an economy is given by the following aggregate production function: Yt = Kt + Nt where Kt is capital
shusha [124]

Answer:

Check the explanation

Explanation:

Yt = Kt + Nt

Taking output per worker, we divide by Nt

Yt/Nt = Kt/Nt + 1

yt = kt + 1

where yt is output per worker and kt is capital per worker.

a) With population being constant, savings rate s and depreciation rate δ.

ΔKt = It - δKt

dividing by Nt, we get

ΔKt/Nt = It/Nt - δKt/Nt ..... [1]

for kt = Kt/Nt, taking derivative

d(kt)/dt = d(Kt/Nt)/dt ... since Nt is a constant, we have

d(kt)/dt = d(Kt/Nt)/dt = (dKt/dt)/Nt = ΔKt/Nt = It/Nt - δKt/Nt = it - δkt

thus, Capital accumulation Δkt = i – δkt

In steady state, Δkt = 0

That is I – δkt = 0

S = I means that I = s.yt

Thus, s.yt – δkt = 0

Then kt* = s/δ(yt) = s(kt+1)/(δ )

kt*= skt/(δ) + s/(δ)

kt* - skt*/(δ) = s/(δ)

kt*(1- s/(δ) = s/(δ)

kt*((δ - s)/(δ) = s/(δ)

kt*(δ-s)) = s

kt* = s/(δ -s)

capital per worker is given by kt*

b) with population growth rate of n,

d(kt)/dt = d(Kt/Nt)/dt =

= \frac{\frac{dKt}{dt}Nt - \frac{dNt}{dt}Kt}{N^{2}t}

= \frac{dKt/dt}{Nt} - \frac{dNt/dt}{Nt}.\frac{Kt}{Nt}

= ΔKt/Nt - n.kt

because (dNt/dt)/Nt = growth rate of population = n and Kt/Nt = kt (capital per worker)

so, d(kt)/dt = ΔKt/Nt - n.kt

Δkt = ΔKt/Nt - n.kt = It/Nt - δKt/Nt - n.kt ......(from [1])

Δkt = it - δkt - n.kt

at steady state Δkt = it - δkt - n.kt = 0

s.yt - (δ + n)kt = 0........... since it = s.yt

kt* = s.yt/(δ + n) =s(kt+1)/(δ + n)

kt*= skt/(δ + n) + s/(δ + n)

kt* - skt*/(δ + n) = s/(δ + n)

kt*(1- s/(δ + n)) = s/(δ + n)

kt*((δ + n - s)/(δ + n)) = s/(δ + n)

kt*(δ + n -s)) = s

kt* = s/(δ + n -s)

.... is the steady state level of capital per worker with population growth rate of n.

3. a) capital per worker. in steady state Δkt = 0 therefore, growth rate of kt is zero

b) output per worker, yt = kt + 1

g(yt) = g(kt) = 0

since capital per worker is not growing, output per worker also does not grow.

c)capital.

kt* = s/(δ + n -s)

Kt*/Nt = s/(δ + n -s)

Kt* = sNt/(δ + n -s)

taking derivative with respect to t.

d(Kt*)/dt = s/(δ + n -s). dNt/dt

(dNt/dt)/N =n (population growth rate)

so dNt/dt = n.Nt

d(Kt*)/dt = s/(δ + n -s).n.Nt

dividing by Kt*

(d(Kt*)/dt)/Kt* = s/(δ + n -s).n.Nt/Kt* = sn/(δ + n -s). (Nt/Kt)

\frac{sn}{\delta +n-s}.\frac{Nt}{Kt}

using K/N = k

\frac{s}{\delta +n-s}.\frac{n}{kt}

plugging the value of kt*

\frac{sn}{\delta +n-s}.\frac{(\delta + n -s)}{s}

n

thus, Capital K grows at rate n

d) Yt = Kt + Nt

dYt/dt = dKt/dt + dNt/dt = s/(δ + n -s).n.Nt + n.Nt

using d(Kt*)/dt = s/(δ + n -s).n.Nt from previous part and that (dNt/dt)/N =n

dYt/dt = n.Nt(s/(δ + n -s) + 1) = n.Nt(s+ δ + n -s)/(δ + n -s) = n.Nt((δ + n)/(δ + n -s)

dYt/dt = n.Nt((δ + n)/(δ + n -s)

dividing by Yt

g(Yt) = n.(δ + n)/(δ + n -s).Nt/Yt

since Yt/Nt = yt

g(Yt) = n.(δ + n)/(δ + n -s) (1/yt)

at kt* = s/(δ + n -s), yt* = kt* + 1

so yt* = s/(δ + n -s) + 1 = (s + δ + n -s)/(δ + n -s) = (δ + n)/(δ + n -s)

thus, g(Yt) = n.(δ + n)/(δ + n -s) (1/yt) =  n.(δ + n)/(δ + n -s) ((δ + n -s)/(δ + n)) = n

therefore, in steady state Yt grows at rate n.

5 0
3 years ago
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