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Scilla [17]
3 years ago
10

suppose you to multiply a whole number greater than 1 by the fraction3/5. will the product be greater than, less than, or equal

to 3/5?
Mathematics
1 answer:
balandron [24]3 years ago
6 0
The product will be greater than 3/5, but less than the number you multiply it by. For example, 2 x 3/5 is 6/5 or 1 and 1/5, which is greater than 3/5, but less than 2.
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A test has 20 questions and is worth 100 points. The unit rate is Points per question?
babunello [35]

Answer:

15

Step-by-step explanation:

6 0
3 years ago
What is the product?<br> (6r-1)(-88-3)
8090 [49]

(6r-1)(-88-3)

Multiply the two brackets together

(6r)(-88)=-528r

(6r)(-3)=18r

(-1)(-88)=88

(-1)(-3)=3

-528r-18r+88+3 ( combine like terms)

Answer: -546r+91

4 0
3 years ago
For the function g(x)=3-8(1/4)^2-x
Reika [66]

Using function concepts, it is found that:

  • a) The y-intercept is y = 2.5.
  • b) The horizontal asymptote is x = 3.
  • c) The function is decreasing.
  • d) The domain is (-\infty,\infty) and the range is (-\infty,3).
  • e) The graph is given at the end of the answer.

------------------------------------

The given function is:

g(x) = 3 - 8\left(\frac{1}{4}\right)^{2-x}

------------------------------------

Question a:

The y-intercept is g(0), thus:

g(0) = 3 - 8\left(\frac{1}{4}\right)^{2-0} = 3 - 8\left(\frac{1}{4}\right)^{2} = 3 - \frac{8}{16} = 3 - 0.5 = 2.5

The y-intercept is y = 2.5.

------------------------------------

Question b:

The horizontal asymptote is the limit of the function when x goes to infinity, if it exists.

\lim_{x \rightarrow -\infty} g(x) = \lim_{x \rightarrow -\infty} 3 - 8\left(\frac{1}{4}\right)^{2-x} = 3 - 8\left(\frac{1}{4}\right)^{2+\infty} = 3 - 8\left(\frac{1}{4}\right)^{\infty} = 3 - 8\frac{1^{\infty}}{4^{\infty}} = 3 -0 = 3

--------------------------------------------------

\lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} 3 - 8\left(\frac{1}{4}\right)^{2-x} = 3 - 8\left(\frac{1}{4}\right)^{2-\infty} = 3 - 8\left(\frac{1}{4}\right)^{-\infty} = 3 - 8\times 4^{\infty} = 3 - \infty = -\infty

Thus, the horizontal asymptote is x = 3.

--------------------------------------------------

Question c:

The limit of x going to infinity of the function is negative infinity, which means that the function is decreasing.

--------------------------------------------------

Question d:

  • Exponential function has no restrictions in the domain, so it is all real values, that is (-\infty,\infty).
  • From the limits in item c, the range is: (-\infty,3)

--------------------------------------------------

The sketching of the graph is given appended at the end of this answer.

A similar problem is given at brainly.com/question/16533631

8 0
2 years ago
12 problems in45 mins 20 problems in how much time
Anni [7]

Answer:

75 mins or 1 hour 15 min :)

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
What is the equation of the line that is parallel to y-3x=2 and that passes through (6,1)?
Rudik [331]

Slope-intercept form:  y = mx + b

(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)

For lines to be parallel, they need to have the same slope.

y - 3x = 2      Add 3x on both sides to change the equation to slope-intercept form

y - 3x + 3x = 2 + 3x

y = 3x + 2   The slope is 3, so the parallel line's slope is also 3.

Now that you know the slope, substitute/plug it into the equation

y = mx + b

y = 3x + b    To find "b", plug in the point (6, 1) into the equation, then isolate/get the variable "b" by itself

1 = 3(6) + b  

1 = 18 + b     Subtract 18 on both sides to get "b" by itself

1 - 18 = 18 - 18 + b

-17 = b

y = 3x - 17    Your answer is the 1st option

8 0
3 years ago
Read 2 more answers
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