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Arte-miy333 [17]
3 years ago
11

PLEASE HELP

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
4 0
(-1, 0) is a x-intercept graphed
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Someone pls help me :((((
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9.2  this is because

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One third the sum of two numbers is 23.If one of the numbers is 29.3,what is the other number​
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The admission fee at an amusement park is $1.50 for children and $4 for adults. On a certain day 333 people enter the park, the
liberstina [14]

Answer:

<u>188 children</u> and <u>145 adults</u> were admitted in the park.

Step-by-step explanation:

Given:

The admission fee at an amusement park is $1.50 for children and $4 for adults.

Total $862 collected on a certain day when 333 people enter the park.

Now, to find the children and adults admitted in the park.

<u><em>Let the number of children admitted be </em></u>x.<u><em /></u>

<u><em>And the the number of adults admitted be </em></u>y.<u><em /></u>

So, the total people enter the park:

x+y=333\\\\x=333-y\ \ \ ...(1)

Thus, the total amount collected of the admission fee:

1.50(x)+4(y)=862\\\\

Substituting the value of x from equation (1):

1.50(333-y)+4(y)=862\\\\499.50-1.50y+4y=862\\\\499.50+2.50y=862\\\\Subtracting\ both\ sides\ by\ 499.50\ we\ get:\\\\2.50y=362.50\\\\Dividing\ both\ sides\ by\ 2.50\ we\ get:\\\\y=145.

<u><em>Thus, the number of adults = 145.</em></u>

Now, to get the number of children by substituting the value of y in equation (1) we get:

x=333-y\\\\x=333-145\\\\x=188.

<u><em>Hence, the number of children = 188.</em></u>

Therefore, 188 children and 145 adults were admitted in the park.

4 0
3 years ago
1. A professional basketball used for league play has a diameter of 25 cm. Which of the following is closest to the volume of th
yKpoI14uk [10]

Answer:

V = 8,181.23 cm^{3}

Step-by-step explanation:

Unfortunately, we are not given any answer choices to choose from but using the information provided we can find the actual volume of the basketball. A basketball is made in the shape of a sphere and the formula for the volume of a sphere is the following...

V = \frac{4}{3} * \pi  * r^{3}

radius of a circle/sphere is half of it's diameter. Since we are provided the diameter size we simply divide it by 2 which would give us 12.5cm. Now we simply plug this value into the formula and solve for V.

V = \frac{4}{3} * \pi  * 12.5^{3}

V = \frac{4}{3}  * \pi  * 1953.125

V = 8,181.23 cm^{3}

5 0
3 years ago
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