Answer:
9.3
Step-by-step explanation:
2/.214
Answer:y = 7x + 5
Step-by-step explanation: does it matter which point it goes through?
(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.
---------------------------------------------------------------------------------------
(b) The following functions are positive in quadrant III:
tangent, cotangent
The following functions are negative in quadrant III
cosine, sine, secant, cosecant
A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.
Answer:
There are 729 possible results are there for the series
Step-by-step explanation:
If we have n trials, each with m possible outcomes, the total number of possible outcomes is:
In this question:
6 games(trials), so 
.
Each with three possible outcomes, so 
Then:
There are 729 possible results are there for the series
Easy 7x3 is first then 7x4 then 7x5=7x_
