3 years ago

What is the formula for the following geometric sequence? -5, -10, -20, -40, ... an = -5 · 2n - 1 an = -5 · (-2)n - 1 an = -2 ·

(-5)n - 1 an = 2 · (-5)n - 1

1 answer:

vazorg [7]3 years ago

8 0

$-5 * 2^{n-1}$

You might be interested in

Nastasia [14]

$(r^{3})^{-3}$
$\frac{1}{(r^{3})^{3}}$

$\frac{1}{(r^{3})(r^{3})(r^{3})}$

$\frac{1}{r^{9}}$

3 0

3 years ago

8090 [49]

24.34 that's true ~~~~~~~~`

3 0

3 years ago

liq [111]

Answer:

∂u/∂xi = i·cos(sn)

Step-by-step explanation:

For u = sin(v), the partial derivative of u with respect to xi is ...

∂u/∂xi = cos(v)·∂v/xi

In this case, v=sn, and ∂sn/∂xi = i, so the derivatives of interest are ...

∂u/∂xi = i·cos(sn)

6 0

3 years ago

Stels [109]

3x³ + x + 2x³ - 4x² - 2(y + x)
3x³ + 2x³ - 4x² + x - 2(y) - 2(x)
5x³ - 4x² + x - 2y - 2x
5x³ - 4x² + x - 2x - 2y
5x³ - 4x² - x - 2y

3 0

3 years ago

nataly862011 [7]

Answer:

406794000

Step-by-step explanation:

3 0

3 years ago