Answer:
Suppose Y is a random variable with mu Subscript Upper YμY = 0, and sigma Subscript Upper Y Superscript 2σ2Y = 1, skewness = 0, and kurtosis = 100.
n random variables drawn from this distribution might have some large outliers due to the reason that there might be some outliers because the kurtosis of the distribution equals 100..
Option A.
Explanation:
From the question, the rate of the description of the data given will not give rise to outliers in the random sample drawn from the population.
Therefore, there might be some outliers because the kurtosis of the distribution equals 100 - Option A.
.... She attempts to influence her clients to switch to printing on the new materials. This is known as a proactive type of approach
This is further explained below.
<h3>What is
a proactive type of approach?</h3>
Generally, Proactive actions prepare for the future. Proactivity is a desired attribute in an individual, team, or organization. Reactive methods wait for the future to happen before acting.
In conclusion, "Loretta is a product manager at a popular printing company. Though none of her small business clients have requested to print on recycled paper, Loretta decides to stock some recycled paper products anyway because she sees this as an opportunity to increase her company’s reputation for sustainability. She attempts to influence her clients to switch to printing on the new materials." is a proactive type of approach
Read more about the proactive type of approach
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D is the answer I’m sure of it
Answer:
when sea transportation is used:
safety stock = Z-score x √lead time x standard deviation of demand
- Z-score for 99% = 2.58
- lead time = 36 days
- standard deviation of demand = 4,000 units
safety stock = 2.58 x √36 x 4,000 units = 61,920 units
reorder point = lead time demand + safety stock
- lead time demand = 36 days x 5,000 units = 180,000 units
- safety stock = 61,920
reorder point = 180,000 units + 61,920 units = 241,920 units
when air transportation is used:
safety stock = Z-score x √lead time x standard deviation of demand
- Z-score for 99% = 2.58
- lead time = 4 days
- standard deviation of demand = 4,000 units
safety stock = 2.58 x √4 x 4,000 units = 20,640 units
reorder point = lead time demand + safety stock
- lead time demand = 4 days x 5,000 units = 20,000 units
- safety stock = 20,640
reorder point = 20,000 units + 20,640 units = 40,640 units
Answer:
$128,477
Explanation:
Given that
Payment to finance for purchasing the machine = $30,500
Rate of interest = 6%
Future value of one for five periods at 6% is 1.33823
The future value of an ordinary annuity for five periods at 6% is 5.63709.
The present value of an ordinary annuity for five periods at 6% is 4.21236.
So by considering the above information, the cost of the machine is
= Payment to finance for purchasing the machine × present value of an ordinary annuity for five periods at 6%
= $30,500 × 4.21236
= $128,477
