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Law Incorporation [45]
2 years ago
14

What is the circumference of the circle if r = 3,5 feet?

Mathematics
1 answer:
Nady [450]2 years ago
8 0

Answer:

21.98

Step-by-step explanation:

C=2πr C=2d are the formulas of circumference so that would mean the diameter of the circle is 7 since 2 times the radius is the diameter. We then multiply the diameter 7 by PI to get 21.98

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Write an equation to represent the problem. Then solve the equation. Two years of local Internet service costs $685, including t
iren2701 [21]

Answer:

(Total - Fee) / Months = $Price per Month

(685 - 85) / 24 = 25

Step-by-step explanation:

4 0
3 years ago
IN THE FIGURE BC IS PARALLEL TO AD. AREA OF TRIANGLE ABC IS 100 cm². WHAT IS THE AREA OF TRIANGLE BCD
Anuta_ua [19.1K]

Answer:

150 cm2

Step-by-step explanation:

double of triangle abc is 200

this is in middle of both

3 0
2 years ago
Which expression is equivalent to g/5h?<br> 7g/15h<br> 2g/10h<br> g-4/5h-4
lianna [129]

Answer:

g-4/5h-5

Step-by-step explanation:

Really easy

6 0
3 years ago
Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your
Veronika [31]

The expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Given an integral \int\limits^5_b {1} \, x/(2+x^{3}) dx.

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

\int\limits^b_a {f(x)} \, dx=\lim_{n \to \infty}∑f(a+iΔx)Δx ,here Δx=(b-a)/n

\int\limits^5_1 {x/(2+x^{3}) } \, dx=f(x)=x/2+x^{3}

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)=[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}

\lim_{n \to \infty}∑f(a+iΔx)Δx=

\lim_{n \to \infty}∑n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n

=4\lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3}

Hence the expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

#SPJ4

5 0
1 year ago
(2x−12)+( 1 2 xy−10) (2x-12)+(12xy-10) for x=8 x=8 and y=2
Ratling [72]
(2(8)-12)+(12(8)(2)-10)
(16-12)+(132-10)
4+122=126
THE ANSWER WOULD BE 126 :D

5 0
3 years ago
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