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exis [7]
3 years ago
15

You have 16 different cuts of flowers and plan to use seven of them how many different selections of the seven flowers are possi

ble
Mathematics
1 answer:
alisha [4.7K]3 years ago
6 0

We can have 11440 different selections.

<u>SOLUTION: </u>

Given, you have 16 different cuts of flowers  

And you have planned to use seven out of them.  

We have to find how many different selections of the seven flowers are possible.  Now, we have to select 7 items out of 16 available items. So we have to use combinations.

Then, 7 out of 16 combination \rightarrow^{16} \mathrm{c}_{7} \rightarrow \frac{16 !}{(16-7) ! 7 !}

\bold{\text{ Since } ^nC_r=\frac{n !}{(r !(n-r) !)}}

\begin{array}{l}{\rightarrow \frac{16 !}{9 ! \times 7 !}} \\\\ {\rightarrow \frac{16 \times 15 \times 14 \times 13 \times 12 \times 11 \times 10 \times 9 !}{9 ! \times 7 !}} \\\\ {\rightarrow \frac{16 \times 15 \times 14 \times 13 \times 12 \times 11 \times 10}{7 \times 6 \times 13 \times 12 \times 11 \times 10}} \\\\ {\rightarrow \frac{57657600}{5040}} \\\\ {\rightarrow 11440}\end{array}

Hence, we can have 11440 different selections.

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3 0
3 years ago
Please solve this, 50 points and BRAINLIEST<br> -4•6/7•-5/3
AleksandrR [38]

Answer:

5 5/7

Step-by-step explanation:

-4•6/7•-5/3

Put the numbers as fractions

-4/1•6/7•-5/3

Rewriting

-4/1 * 6/3 * -5/7

Simplifying the middle fraction

-4/1 * 2/1 * -5/7

Multiply the first two terms

-8/1 * -5/7

Multiplying

40/7

Changing from an improper fraction to a mixed number

7 goes into 40 5 times with 5 left over

5 5/7

4 0
3 years ago
Read 2 more answers
The greenhouse club is purchasing seed for the lawn in the school courtyard. The club needs to determine how much to buy. Unfort
kiruha [24]

Answer:

The answer is 2940ft^2

Step-by-step explanation

First convert length and width to feet using the value given (7ft=1inch).

10*7= 70

6*7= 42

Multiply these values for the actual area.

42*70= 2940

The actual area of the lawn is 2940ft^2

7 0
3 years ago
Your turn! 6/8 divided 2/8​
just olya [345]

Answer:

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3 years ago
What is the sum of the first 4 terms of the arithmetic sequence in which the 8th term is 10 and the 14th term is 29.5?
Sholpan [36]

Answer:

Sum of the first 4 terms is

14.50

Explanation:

In an arithmetic sequence, whose first term is

a

and difference between a term and its preceding term is

d

,

the

n

t

h

term is

a

+

(

n

−

1

)

d

and sum of first

n

terms is

n

2

(

2

a

+

(

n

−

1

)

d

)

Hence

6

t

h

term will be

a

+

5

d

=

8

and

10

t

h

term will be

a

+

9

d

=

13

Subtracting first from second,

4

d

=

5

or

d

=

1.25

and

a

=

8

−

5

⋅

1.25

=

8

−

6.25

=

1.75

Hence sum of first four terms is

4

2

⋅

(

2

⋅

1.75

+

3

⋅

1.25

)

=

2

⋅

(

3.5

+

3.75

)

=

2

⋅

7.25

=

14.50

8 0
2 years ago
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