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vfiekz [6]
3 years ago
8

Evaluate p+(-q)-2 where p = 3 and Q =5

Mathematics
1 answer:
Ad libitum [116K]3 years ago
4 0

Answer:

-4

Step-by-step explanation:

3+(-5)-2

3+-5-2

3-7

=-4

You might be interested in
A six-sided fair dle is rolled 4 times in a row. The probability of getting a 4 only on the last trial is ______
4vir4ik [10]

Answer:

1/6

Step-by-step explanation:

No. Of faces contains 4=1

Total no. Of faces=6

Probablity = favourable no. of outcomes/Total no. of outcomes

PLEASE GIVE BRAINLIEST

4 0
3 years ago
How do you solve his with working
AlexFokin [52]
Check the picture below.

a)

so the perimeter will include "part" of the circumference of the green circle, and it will include "part" of the red encircled section, plus the endpoints where the pathway ends.

the endpoints, are just 2 meters long, as you can see 2+15+2 is 19, or the radius of the "outer radius".

let's find the circumference of the green circle, and then subtract the arc of that sector that's not part of the perimeter.

and then let's get the circumference of the red encircled section, and also subtract the arc of that sector, and then we add the endpoints and that's the perimeter.

\bf \begin{array}{cllll}
\textit{circumference of a circle}\\\\ 
2\pi r
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{arc's length}\\\\
s=\cfrac{\theta r\pi }{180}
\end{array}\\\\
-------------------------------

\bf \stackrel{\stackrel{green~circle}{perimeter}}{2\pi(7.5) }~-~\stackrel{\stackrel{green~circle}{arc}}{\cfrac{(135)(7.5)\pi }{180}}~+
\stackrel{\stackrel{red~section}{perimeter}}{2\pi(9.5) }~-~\stackrel{\stackrel{red~section}{arc}}{\cfrac{(135)(9.5)\pi }{180}}+\stackrel{endpoints}{2+2}
\\\\\\
15\pi -\cfrac{45\pi }{8}+19\pi -\cfrac{57\pi }{8}+4\implies \cfrac{85\pi }{4}+4\quad \approx \quad 70.7588438888



b)

we do about the same here as well, we get the full area of the red encircled area, and then subtract the sector with 135°, and then subtract the sector of the green circle that is 360° - 135°, or 225°, the part that wasn't included in the previous subtraction.


\bf \begin{array}{cllll}
\textit{area of a circle}\\\\ 
\pi r^2
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{area of a sector of a circle}\\\\
s=\cfrac{\theta r^2\pi }{360}
\end{array}\\\\
-------------------------------

\bf \stackrel{\stackrel{red~section}{area}}{\pi(9.5^2) }~-~\stackrel{\stackrel{red~section}{sector}}{\cfrac{(135)(9.5^2)\pi }{360}}-\stackrel{\stackrel{green~circle}{sector}}{\cfrac{(225)(7.5^2)\pi }{360}}
\\\\\\
90.25\pi -\cfrac{1083\pi }{32}-\cfrac{1125\pi }{32}\implies \cfrac{85\pi }{4}\quad \approx\quad 66.75884

7 0
3 years ago
Willie spent half of his weekly allowance on clothes. To earn more money his parents let him weed the garden for $5. What is his
Lera25 [3.4K]

Answer:

14 dollars

Step-by-step explanation:

14÷2= 7

7+5=12

5 0
3 years ago
I have $1500 to invest in an account that pays 1.25% compounded continuously. How much money will I have after 10 years?
S_A_V [24]

I hope you find my answer helpful I got 39,000.

7 0
3 years ago
Point A and point B are placed on a number line. Point A is located at -20 and point B is 5 less than point A. Which statement a
dusya [7]
The correct answer is b im sure.
3 0
3 years ago
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