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Nady [450]
3 years ago
11

A. submarine is at the surface of the ocean preparing to dive .it submerges and dives to -972 feet. then.it has ascends 308 feet

a to avoid hitting an undersea cliff. what interger represents the submarines position in feet(depth) after it ascends to aviod the cliff
Mathematics
1 answer:
lisabon 2012 [21]3 years ago
5 0
The submarine is at -664 feet
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Solve the system of equations x - 2y = – 7 and -3x – 2y = 29 by combining the<br> equations.
Ksivusya [100]

Answer:

x = - 9, y = -1

Step-by-step explanation:

<em>Given:</em>

<em />\begin{bmatrix}x-2y=-7\\ -3x-2y=29\end{bmatrix}

Solve:

\mathrm{Substitute\:}x=-7+2y

\begin{bmatrix}-3\left(-7+2y\right)-2y=29\end{bmatrix}

\begin{bmatrix}21-8y=29\end{bmatrix}

\mathrm{For\:}x=-7+2y

\mathrm{Substitute\:}y=-1

x=-7+2\left(-1\right)

x=-9

\mathrm{Thus, Answer:x=-9,\:y=-1}

[RevyBreeze]

5 0
3 years ago
The pool was full with the dump 60 inches the water was drained out at a rate of 8 in./h right the function for this situation
Kobotan [32]

The pool was full with the dump 60 inches the water was drained out at a rate of 8 in./h right the function for this situation

Let

y -----> the number of inches in the water

x -----> the time in hours

we have that

y=60-8x -----> equation taht represent this situation

3 0
1 year ago
PLS HELP WITH THIS I NEED A GOOD GRADE
Minchanka [31]

Step-by-step explanation:

<h2>4.5 approximately is the answer.</h2>

4 0
3 years ago
A right rectangular prism is packed with cubes of side length fraction 1 over 8 inch. If the prism is packed with 16 cubes along
frez [133]

Answer:

  • A. fraction 1 and 1 over 2 cubic inches

Step-by-step explanation:

Unit cube side = 1/8 in

<u>Volume of prism:</u>

  • V= lwh =
  • 16*(1/8)*8*(1/8)*6*(1/8) =
  • 2*1*3/4 =
  • 3/2 = 1  1/2 cubic inches

Correct option is A

6 0
3 years ago
Candy. Someone hands you a box of a dozen chocolate-covered candies, telling you that half are vanilla creams and the other half
BaLLatris [955]

Answer:

a) P=0.091

b) If there are half of each taste, picking 3 vainilla in a row has a rather improbable chance (9%), but it is still possible that there are 6 of each taste.

c) The probability of picking 4 vainilla in a row, if there are half of each taste, is P=0.030.

This is a very improbable case, so if this happens we would have reasons to think that there are more than half vainilla candies in the box.

Step-by-step explanation:

We can model this problem with the variable x: number of picked vainilla in a row, following a hypergeometric distribution:

P(x=k)=\dfrac{\binom{K}{k}\cdot \binom{N-K}{n-k}}{\binom{N}{n}}

being:

N is the population size (12 candies),

K is the number of success states in the population (6 vainilla candies),

n is the number of draws (3 in point a, 4 in point c),

k is the number of observed successes (3 in point a, 4 in point c),

a) We can calculate this as:

P(x=3)=\dfrac{\binom{6}{3}\cdot \binom{12-6}{3-3}}{\binom{12}{3}}=\dfrac{\binom{6}{3}\cdot \binom{6}{0}}{\binom{12}{3}}=\dfrac{20\cdot 1}{220}=0.091

b) If there are half of each taste, picking 3 vainilla in a row has a rather improbable chance (9%), but is possible.

c) In the case k=4, we have:

P(x=3)=\dfrac{\binom{6}{4}\cdot \binom{6}{0}}{\binom{12}{4}}=\dfrac{15\cdot 1}{495}=0.030

This is a very improbable case, so we would have reasons to think that there are more than half vainilla candies in the box.

4 0
3 years ago
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