Answer:
The required probability = 0.9345
Step-by-step explanation:
Given that:
p = 0.17
n = 6
The required probability that two or less light bulbs are defective = (P<2)
(P<2) = P(X=0) +P(X=1) +P(X=2)
Answer:
13 units
Step-by-step explanation:
Hypotenuse theory
+ =
-3×2= -6
-6-27= -33
so if we peak option B.
(-3x +91)(x+31)
solving it
-3x (x+31)+91(x+31)
-3x^2 -93x +91x +2821
we will take (-93x+91x)= -2x
so it's going to be
-3x^2 -2x +2821
this is a quadratic equation hence
2+/-√-2^2-(4×-3×2821)divided by 2×-3
2+/-√4+33852divide by -6
2+/-√33856 divide by -6
2+/- 184 divided by -6
2+/- 30.67
when you add you'll get
32.67
round it off and you get 33
which is the same as what we got at the top
so expression B is the same as
-3×2-27 which is 33
Step-by-step explanation:
Clue: (I'm not giving the answer this is just clues) The word "absolute" helps you understand not to estimate so you want to get the RIGHT answer not the estimation.
Well I think it is F bc it is asking to compare the two numbers of the books that Mary and Paul have not adding