Can someone show me what I need to do here
1 answer:
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Hey there.
7q - 5
10q + 19
Get the variable to one side.
-5 3q + 19
Isolate the variable.
3q
24
Solve for the variable.
q 8 is your answer.
I hope this helps!
7q - 5
Get the variable to one side.
-5
Isolate the variable.
3q
Solve for the variable.
q
I hope this helps!
Answer:
2 m/s
Step-by-step explanation:
Given the graph of the baseball thrown into air.
John throws the baseball into the air from a given height and then the baseball reaches a maximum height and then comes back to ground.
The height of the baseball (in metres) is modeled by the function graph with respect to time.
To find:
The average rate of change of height of the ball from the point the ball is thrown to the maximum height.
Solution:
Here, the average rate of change can be found by dividing the distance between the two points with the change in time.
The starting time is 0 seconds.
The starting height is 3 metres.
The ending time is 2 seconds i.e. at which the ball reaches the maximum height.
The height is 7 metres.
Therefore, the average rate of change is:
Answer:
d ≈ 6.41
Step-by-step explanation:
Given that F is inversely proportional to d² then the equation relating them is
F = ← k is the constant of proportion
To find k use the condition when F = 8, d = 6 , then
8 = =
( multiply both sides by 36 )
288 = k
F = ← equation of proportion
When F = 7 , then
7 = ( multiply both sides by d² )
d² × 7 = 288 ( divide both sides by 7 )
d² = ( take the square root of both sides )
d = ± ≈ ± 6.41
The positive value of d is 6.41 ( to 2 dec. places )