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3 years ago

5

The ratio of women to men in this university is 60:40, suppose the number of students in this class is 20, and i ask what number

x of women would make this class 60:40.

1 answer:

BabaBlast [244]3 years ago

4 0

3:2 ratio --> the answer is 12 btw

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A used bookstore will trade 2 of its books for 3 of yours. If Val brings in 18 books to trade, How many books can she get from t

dolphi86 [110]

Answer:

She will get 12 books from the store

Step-by-step explanation:

We can use ratio's to solve

2 books out x books out

------------------- =-----------------------------

3 books in 18 books in from Val

Using cross products

2 * 18 = 3 *x

Divide each side by 3

2*18 /3 = 3x/3

2*6 = x

12 =x

She will get 12 books from the store

8 0

3 years ago

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Can someone find the surface area for this? :)

AysviL [449]

Answer:

84 :)

Step-by-step explanation:

bottom surface area= $6m^{2}$

top surface area= $6m^{2}$

lateral surface area= $72m^{2}$

add this together you get TOTAL surface area of 84

3 0

3 years ago

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If f(x) = 53 - 2x, then f(-3) =

zheka24 [161]

Substitute -3 for x in the expression

f(x)= 53 - 2x

f(-3)= 53 - 2(-3)
multiply -2 * -3

f(-3)= 53 + 6
add

f(-3)= 59

ANSWER: f(-3)= 59

Hope this helps! :)

4 0

3 years ago

One of the tables shows a proportional relationship. Graph the line representing the proportional relationship from this table i

Mkey [24]

Answer:

Table C

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $y/x=k$ or $y=kx$

Find the value of the constant of proportionality in each table

Table A

For $x=-2, y=-4$ ------> $k=-4/-2=2$

For $x=-1, y=-3$ ------> $k=-3/-1=3$

This table has different values of k

therefore

the table A does not represent a proportional relationship

Table B

For $x=-2, y=-4$ ------> $k=-4/-2=2$

For $x=-1, y=-2$ ------> $k=-2/-1=2$

For $x=1, y=3$ ------> $k=3/1=3$

This table has different values of k

therefore

the table B does not represent a proportional relationship

Table C

For $x=-2, y=-4$ ------> $k=-4/-2=2$

For $x=-1, y=-2$ ------> $k=-2/-1=2$

For $x=1, y=2$ ------> $k=2/1=2$

For $x=2, y=4$ ------> $k=4/2=2$

This table has the same value of k

therefore

the table C represent a proportional relationship

Table D

For $x=-2, y=-4$ ------> $k=-4/-2=2$

For $x=-1, y=-2$ ------> $k=-2/-1=2$

For $x=1, y=2$ ------> $k=2/1=2$

For $x=2, y=6$ ------> $k=6/2=3$

This table has different values of k

therefore

the table D does not represent a proportional relationship

3 0

3 years ago

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2(8r+5)-3=4(4r-1)+11 is it an only solution or a no solution or infinite solution

pogonyaev

Answer:

Infinitely many solutions.

Step-by-step explanation:

Let's begin by carrying out the indicated multiplications, which must be done before any addition or subtraction:

2(8r+5)-3=4(4r-1)+11 becomes 16r + 10 - 3 = 16r - 4 + 11.

Subtracting 16r from both sides, we get 10 - 3 = - 4 + 11, or 7 = 7

This is always true, so we can conclude that this equation has infinitely many solutions.

3 0

2 years ago