X^2+12x-28
(x-2)(x+14)
Solve for x
x-2=0
x=2
x+14=0
x=-14
Answer:
10z+34
Step-by-step explanation:
x/2 + 4 < 7
multiply both sides by 2
x/2 * 2 + 4 * 2 < 7 * 2
which equals
x + 8 < 14
subtract 8 from both sides
x + 8 - 8 < 14 - 8
x < 6
Value of x is 10
Step-by-step explanation:
- Step 1: Here, x is the hypotenuse of the right angled triangle. Use the trigonometric ratio cosine to find x.
cos 28° = adjacent side/hypotenuse = 11/x
⇒ x = 11/cos 28° = 11/-0.96 = -11.46 ≈ 10 (rounding off to nearest tenth)