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fenix001 [56]
3 years ago
14

Must Just one match to fix the equation ? 6 + 4 = 4

Mathematics
2 answers:
givi [52]3 years ago
4 0
You could put a match over the equal sign. Turn this equals into this does not equal.

This would look like this:

6+4 ≠4

And that would be your answer! Hope this helps :)
zhannawk [14.2K]3 years ago
3 0

Answer:

6 + 4 × -2/4 = 4

Step-by-step explanation:

hi hope u understand

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How to expand the number 2,937,082​
denis-greek [22]
2x1,000,000
9x100,000
3x10,000
7x1,000
0x100
8x10
2x1
7 0
3 years ago
A production process produces 2% defective parts. a sample of 5 parts from the production is selected. what is the probability t
Lana71 [14]

Answer:

Probability of a sample that contains exactly two defective parts is .0037 or .37%

Step-by-step explanation:

As we know if P is the probability of achieving k results in n trials then probability formula is P = \binom{n}{k}p^{K}q^{n-k}

In this formula n = number of trials

                        k = number of success

                        (n-k) = number of failures

                         p = probability of success in one trial

                         q = (1-p) = probability of failure in one trial

In this sum n = 5

                  k = 2

number failures (n-k) = (5-2) = 3

                            p = 2% which can be written as .02

                            q = 98% Which can be written as .98

Now putting these values in the formula

                        P = \binom{5}{2}(.02)^{2}(.98)^{5-2}

                        P = \binom{5}{2}(.02)^{2}(.98)^{3}

                   \binom{5}{2}= 5!/3!2!    

                                              = 5×4×3×2×1/3×2×1×2×1

                                              = 5×2 =10

                                       P = 10×(.02)²×(.98)³

                                          = .0037 or .37%

4 0
3 years ago
Read 2 more answers
If h(x) = 6 – x, what is the value of (h circle h) (10)?<br> –4<br> –2<br> 10<br> 16
Ganezh [65]

Answer:

10

Step-by-step explanation:

Here, we want to find the value of ;

h circle h(10)

This mean we are to put h in h, the find the function of 10

we have this as;

6-(6-x)

= 6-6 + x = x

Now, replace the x by 10; so we have h circle h(10)

5 0
3 years ago
Read 2 more answers
The joint probability density function of X and Y is given by fX,Y (x, y) = ( 6 7 x 2 + xy 2 if 0 &lt; x &lt; 1, 0 &lt; y &lt; 2
fredd [130]

I'm going to assume the joint density function is

f_{X,Y}(x,y)=\begin{cases}\frac67(x^2+\frac{xy}2\right)&\text{for }0

a. In order for f_{X,Y} to be a proper probability density function, the integral over its support must be 1.

\displaystyle\int_0^2\int_0^1\frac67\left(x^2+\frac{xy}2\right)\,\mathrm dx\,\mathrm dy=\frac67\int_0^2\left(\frac13+\frac y4\right)\,\mathrm dy=1



b. You get the marginal density f_X by integrating the joint density over all possible values of Y:

f_X(x)=\displaystyle\int_0^2f_{X,Y}(x,y)\,\mathrm dy=\boxed{\begin{cases}\frac67(2x^2+x)&\text{for }0

c. We have

P(X>Y)=\displaystyle\int_0^1\int_0^xf_{X,Y}(x,y)\,\mathrm dy\,\mathrm dx=\int_0^1\frac{15}{14}x^3\,\mathrm dx=\boxed{\frac{15}{56}}

d. We have

\displaystyle P\left(X

and by definition of conditional probability,

P\left(Y>\dfrac12\mid X\frac12\text{ and }X

\displaystyle=\dfrac{28}5\int_{1/2}^2\int_0^{1/2}f_{X,Y}(x,y)\,\mathrm dx\,\mathrm dy=\boxed{\frac{69}{80}}

e. We can find the expectation of X using the marginal distribution found earlier.

E[X]=\displaystyle\int_0^1xf_X(x)\,\mathrm dx=\frac67\int_0^1(2x^2+x)\,\mathrm dx=\boxed{\frac57}

f. This part is cut off, but if you're supposed to find the expectation of Y, there are several ways to do so.

  • Compute the marginal density of Y, then directly compute the expected value.

f_Y(y)=\displaystyle\int_0^1f_{X,Y}(x,y)\,\mathrm dx=\begin{cases}\frac1{14}(4+3y)&\text{for }0

\implies E[Y]=\displaystyle\int_0^2yf_Y(y)\,\mathrm dy=\frac87

  • Compute the conditional density of Y given X=x, then use the law of total expectation.

f_{Y\mid X}(y\mid x)=\dfrac{f_{X,Y}(x,y)}{f_X(x)}=\begin{cases}\frac{2x+y}{4x+2}&\text{for }0

The law of total expectation says

E[Y]=E[E[Y\mid X]]

We have

E[Y\mid X=x]=\displaystyle\int_0^2yf_{Y\mid X}(y\mid x)\,\mathrm dy=\frac{6x+4}{6x+3}=1+\frac1{6x+3}

\implies E[Y\mid X]=1+\dfrac1{6X+3}

This random variable is undefined only when X=-\frac12 which is outside the support of f_X, so we have

E[Y]=E\left[1+\dfrac1{6X+3}\right]=\displaystyle\int_0^1\left(1+\frac1{6x+3}\right)f_X(x)\,\mathrm dx=\frac87

5 0
3 years ago
Find the indicated term of the given arithmetic sequence.<br><br> a14 for 200, 196, 192, ...
Fofino [41]

Answer:

148

Step-by-step explanation:

AP 200, 196, 192, ...

a14=?

---------

a1= 200

d= 196-200=192-196= -4

a14= a1+13d

a14= 200+13*(-4)= 200- 52= 148

3 0
4 years ago
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