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katrin [286]
3 years ago
15

What is the distance between the points (7, 8) and (–8, 0) on a coordinate grid?

Mathematics
2 answers:
Sidana [21]3 years ago
8 0

Good morning,

Answer:

<h2>17</h2>

Step-by-step explanation:

Let M(-8,0) and N(7,8)

MN² = (7-(-8))²+(8-0)² = 289

Then

MN = √(289) = 17.

:)

charle [14.2K]3 years ago
5 0

Answer:

the distance is 17 units

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galben [10]

Answer:

x-intercept = (-8, 0)

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Step-by-step explanation:

Given linear equation is: x + 4y = - 8

For x - intercept: Plug y = 0 in the above equation.

\implies x +4(0) = -8\\\\\implies x +0 =-8\\\\ \implies x = -8\\\\ \boxed{\red{\bold{\implies x- intercept = (-8,\:0)}}}

For y - intercept: Plug x = 0 in the given linear equation.

\implies 0 +4y = -8\\\\\implies 4y=-8\\\\ \implies y = \frac{-8}{4}\\\\ \implies y = -2\\\\ \boxed{\purple{\bold{\implies y- intercept = (0,\:-2)}}}

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Step-by-step explanation:

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Answer:

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Andrew is riding his bike. He biked a distance of 14 miles at a rate of 7 miles per hour. Using the distance formula, d = it, so
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

\Sigma_{k=1}^{16} (k - 5)^2 \\= (1- 5)^2 +  (2- 5)^2 +  (3- 5)^2 + \\ (4- 5)^2 +  (5- 5)^2 +  (6- 5)^2 \\+  (7- 5)^2 +  (8- 5)^2 +  (9- 5)^2 \\+  (10- 5)^2 +  (11- 5)^2 +  (12- 5)^2 \\+  (13- 5)^2 +  (14- 5)^2 +  (15- 5)^2\\ +  (16- 5)^2 \\\\=(-4)^2 +  (-3)^2 +  (-2)^2 +  (-1)^2 +  (0)^2 \\+  (1)^2 +  (2)^2 +  (3)^2 +  (4)^2 +  (5)^2 \\+  (6)^2 +  (7)^2 +  (8)^2 +  (9)^2 +  (10)^2 + \\ (11)^2 \\\\=16 + 9 + 4 + 1 + 0 + 1 + 4 + 9 + 16 + 25 \\+ 36 + 49+ 64 + 81 + 100 + 121

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3 years ago
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