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CaHeK987 [17]
3 years ago
14

What is the solution to the equation 9(w – 4) – 7w = 5(3w – 2)?​

Mathematics
2 answers:
Yuliya22 [10]3 years ago
3 0

Answer:

W= -2

Step-by-step explanation:

Simply the expression: 9(w – 4) – 7w = 5(3w – 2)

First step: 9w -36-7w = 15w-10

Second step: 2w-36=15w-10

Third step:-36+10=15w-2w

Fourth step:-26=13w

Fifth step: w=\frac{-26}{13}

Six step: w=-2

evablogger [386]3 years ago
3 0

Answer:

-2=w

Step-by-step explanation:

9(w-4) - 7w= 5(3w-2)

<u>9w</u>-36-<u>7w</u>= 15w - 10

2w-36=15w-10

- 2w      -2w

-36=13w-10

+10         +10

-26= 13w

-2=w

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Answer:

\displaystyle y=\sqrt{\frac{1}{2}x -1}

Step-by-step explanation:

We want to find the inverse of the function:

y=2x^2+2

To find the inverse of a function, we will flip the variables and solve for <em>y</em>. So:

x=2y^2+2

Solve for <em>y</em>. Subtract two from both sides:

x-2=2y^2

Divide both sides by two:

\displaystyle y^2=\frac{1}{2}x-1

And take the principal square root of both sides. Therefore:

\displaystyle y=\sqrt{\frac{1}{2}x -1}

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 If triangle ABC is reflected over the x-axis, rotated 180 degrees, and reflected over the y-axis, where will point B' lie? (5
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Solve the equation 15p2 + 7p − 4 = 0 by completing the square.
natulia [17]

Answer:

p=0 or p=-7/15

Step-by-step explanation:

15p2+7p=0

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4 0
2 years ago
A sample of 15 commuters in Chicago showed the average of the commuting times was 33.2 minutes. If s = 8.3 minutes, find the 95%
OleMash [197]

Answer:

The 95% confidence interval of the true mean.

(29.4261 ,36.9739)

Step-by-step explanation:

<u>Step :- (i)</u>

Given sample size 'n' =15

sample of the mean x⁻ = 33.2

The standard deviation of the sample 'S' = 8.3

<u>95% of confidence intervals</u>

<u></u>(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } ,x^{-} + t_{\alpha }\frac{S}{\sqrt{n} } )<u></u>

<u>Step:-(ii)</u>

<u>The degrees of freedom γ=n-1 = 15-1=14</u>

The tabulated value t = 1.761 at 0.05 level of significance.

now substitute all possible values, we get

(33.2 - 1.761\frac{8.3}{\sqrt{15} } ,33.2+ 1.761\frac{8}{\sqrt{15} } )

After calculation , we get

(33.2-3.7739 , 33.2+3.7739

(29.4261 ,36.9739)

<u>Conclusion</u>:-

the 95% confidence interval of the true mean.

(29.4261 ,36.9739)

8 0
3 years ago
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