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dem82 [27]
3 years ago
5

The area of a rectangular park is 3/5 square mile. the length of the park is 7/8 mile. what is the width of the park

Mathematics
2 answers:
Stells [14]3 years ago
6 0
A=LW so

W=A/L

W=(3/5)/(7/8)

W=(3/5)*(8/7)

W=24/35 mi
tangare [24]3 years ago
3 0
Hello:
<span>remember that Area=Length ×Width
                         3/5 = (7/8) × x
x = (3/5)/(7/8)
x = (3/5)×(8/7)
x =24/25 </span><span>square mile</span>
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In a group of a hundred and fifty students attending a youth workshop in mombasa, 125 of them are fluent in kiswahili, 135 in en
jek_recluse [69]

Answer:

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given total number of students n(T) = 150

Given 125 of them are fluent in Swahili

Let 'S' be the event of fluent in  Swahili language

n(S) = 125

The probability that the fluent in  Swahili language

P(S) = \frac{n(S)}{n(T)} = \frac{125}{150} = 0.8333

Let 'E' be the event of fluent in English language

n(E) = 135

The probability that the fluent in  English language

P(E) = \frac{n(E)}{n(T)} = \frac{135}{150} = 0.9

n(E∩S) = 95

The probability that the fluent in  English and Swahili

P(SnE) = \frac{n(SnE)}{n(T)} = \frac{95}{150} = 0.633

<u><em>Step(ii):</em></u>-

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = P(S) + P(E) - P(S∩E)

           = 0.833+0.9-0.633

           = 1.1

<u><em>Final answer:-</em></u>

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

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Step-by-step explanation:

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Step-by-step explanation:

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<span>2d – e = 7 </span>
<span>d + e = 5 </span>

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<span>d=4 </span>


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