A] David's speed during the period:
i] AB
speed=distance/time
time taken between AB=0.5 hours
distance=20 km
thus
speed=20/0.5=40 km/h
ii]BC
time taken between BC=1.5 hours
distance=20
speed=20/1.5=13 1/3 km/h
b] Average speed for the entire time will be:
average speed=(total distance)/(total time)
total distance=(20+20+20)=60 km
total time=3 hours
thus
average speed=60/3=20 km/h
c] David's distance 2 hours and 15 minutes from the starting point was:
distance=20+20+10=50 km
Answer:
ABD and ABE
Step-by-step explanation:
We have
<span>q^2 - 9 = (q + 3)(g - 3)
</span>q^2 - 9---------------> (q+3)(q-3)
therefore
(q+3)(q-3)=(q + 3)(g - 3)
(q-3)=(g - 3)
q=g
Answer: Most likely (A) and (D)
Answer:
this is the answer
Step-by-step explanation:
42.7893
